Hãy giúp mình với cảm ơn nha
b) -23/28 +x=-11/12
c) 1/4 – |3-x| = -3/4
d) |3/4 x-1/2| -1= 1/4
e) x² : 1/2= 49/12
g) x² . 5/5= 5/27
Hãy giúp mình với cảm ơn nha
b) -23/28 +x=-11/12
c) 1/4 – |3-x| = -3/4
d) |3/4 x-1/2| -1= 1/4
e) x² : 1/2= 49/12
g) x² . 5/5= 5/27
`b)`
`-23/28+x=-11/12`
`=>x=-11/12+23/28`
`=>x=-2/21`
Vậy `x=-2/21`
`c)`
`1/4 – |3-x| = -3/4`
`=>|3-x|=1/4-(-3/4)`
`=>|3-x|=1`
`=>` \(\left[ \begin{array}{l}3-x=1\\3-x=-1\end{array} \right.\) `=>` \(\left[ \begin{array}{l}x=2\\x=4\end{array} \right.\)
Vậy `x\in{2;4}`
`d)`
`|3/4 x-1/2| -1= 1/4`
`=>|3/4x-1/2|=1/4+1`
`=>|3/4x-1/2|=5/4`
`=>` \(\left[ \begin{array}{l}\dfrac{3}{4}x-\dfrac{1}{2}=\dfrac{5}{4}\\\dfrac{3}{4}x-\dfrac{1}{2}=-\dfrac{5}{4}\end{array} \right.\) `=>` \(\left[ \begin{array}{l}x=\dfrac{7}{3}\\x=-1\end{array} \right.\)
Vậy `x\in{-1;7/3}`
`e)`
`x^2:1/2=49/12`
`=>x^2=49/12 . 1/2`
`=>x^2=49/24`
`=>x=+-\sqrt{49/24}`
Vậy `x\in{+-\sqrt{49/24}}`
`g)`
`x^2 . 5/5=5/27`
`=>x^2=5/27:5/5`
`=>x^2=5/27`
`=>x=+-\sqrt{5/27}`
Vậy `x\in{+-\sqrt{5/27}}`
b) -23/28 +x=-11/12
⇔ x=-11/12+23/28
⇔ x=-2/21
c) 1/4 – |3-x| = -3/4
⇔ |3-x| = 1/4+3/4
⇔ |3-x| =1
⇔3-x=1 hoặc 3-x=-1
x=2 x=4
Vậy x=2 hoặc x=4
d) |3/4 x-1/2| -1= 1/4
⇔ |3/4 x-1/2|=1/4+1
⇔ |3/4 x-1/2|=5/4
⇔ 3/4x-1/2=5/4 hoặc 3/4x-1/2=-5/4
⇔ 3/4x=5/4+1/2 3/4x=-5/4+1/2
⇔ 3/4x=7/4 3/4x=-3/4
⇔ x=7/4:3/4 x=-3/4:3/4
⇔ x=7/3 x=-1
e) x² : 1/2= 49/12
⇔x²=49/12 . 1/2
⇔x²= 49/24
⇔x=±√49/24
g) x² . 5/5= 5/27
⇔x²=5/27:5/5
⇔x²=5/27
⇔x=±√5/27
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