help me $2010^{n}$.$2010^{2}$ – $30^{n+2}$.($67^{n+2}$-$30^{2-n}$) 28/07/2021 Bởi Abigail help me $2010^{n}$.$2010^{2}$ – $30^{n+2}$.($67^{n+2}$-$30^{2-n}$)
$2010^{n}$.$2010^{2}$-$30^{n+2}$.($67^{n+2}$-$30^{2-n}$) = $2010^{n+2}$-$30^{n+2}$.$67^{n+2}$+$30^{n+2}$.$30^{2-n}$ = $2010^{n+2}$-$(30.67)^{n+2}$+$30^{n}$+$30^{2}$.$30^{2}$:$30^{n}$ = $2010^{n+2}$-$2010^{n+2}$+$30^{4}$ = $30^{4}$ HỌC TỐT ^^ Bình luận
$2010^{n}$.$2010^{2}$-$30^{n+2}$.($67^{n+2}$-$30^{2-n}$)
= $2010^{n+2}$-$30^{n+2}$.$67^{n+2}$+$30^{n+2}$.$30^{2-n}$
= $2010^{n+2}$-$(30.67)^{n+2}$+$30^{n}$+$30^{2}$.$30^{2}$:$30^{n}$
= $2010^{n+2}$-$2010^{n+2}$+$30^{4}$
= $30^{4}$
HỌC TỐT ^^