Hoàn thành chuỗi phản ứng sau :
`Fe -> Fe_3O_4 -> FeCl_3 -> FeCl_2 -> Fe(OH)_2 -> Fe(OH)_3 -> Fe_2O_3 -> Al -> Al_2O_3 -> Al_2(SO_4)_3 -> Al(OH)_3 -> AlCl_3 -> Al(OH)_3 -> Al_2O_3 -> Al-> NaAlO_2 -> Ba(AlO_2)_2`
Hoàn thành chuỗi phản ứng sau :
`Fe -> Fe_3O_4 -> FeCl_3 -> FeCl_2 -> Fe(OH)_2 -> Fe(OH)_3 -> Fe_2O_3 -> Al -> Al_2O_3 -> Al_2(SO_4)_3 -> Al(OH)_3 -> AlCl_3 -> Al(OH)_3 -> Al_2O_3 -> Al-> NaAlO_2 -> Ba(AlO_2)_2`
$\begin{array}{l} a)\quad Fe \xrightarrow{(1)}Fe_3O_4\xrightarrow{(2)}FeCl_3\xrightarrow{(3)}FeCl_2\xrightarrow{(4)}Fe(OH)_2\xrightarrow{(5)}Fe(OH)_3\xrightarrow{(6)}Fe_2O_3\\ (1)\quad 3Fe + 2O_2 \xrightarrow{\quad t^\circ\quad} Fe_3O_4\\ (2)\quad Fe_3O_4 + 8HCl \longrightarrow FeCl_2 + 2FeCl_3 + 4H_2O\\ (3)\quad Fe +2FeCl_3 \longrightarrow 3FeCl_2\\ (4)\quad FeCl_2 + 2NaOH \longrightarrow Fe(OH)_2\downarrow + 2NaCl\\ (5)\quad 4Fe(OH)_2 + O_2 + 2H_2O\xrightarrow{\quad t^\circ\quad} 4Fe(OH)_3\\ (6)\quad 2Fe(OH)_3 \xrightarrow{\quad t^\circ\quad} Fe_2O_3 + 3H_2O\\ b)\quad Al\xrightarrow{(1)}Al_2O_3\xrightarrow{(2)}Al_2(SO_4)_3\xrightarrow{(3)}Al(OH)_3\xrightarrow{(4)}AlCl_3\xrightarrow{(5)}Al(OH)_3\xrightarrow{(6)}Al_2O_3\xrightarrow{(7)}Al\xrightarrow{(8)}NaAlO_2\xrightarrow{(9)}Ba(AlO_2)_2\\ (1)\quad 4Al + 3O_2\xrightarrow{\quad t^\circ\quad}2Al_2O_3\\ (2)\quad Al_2O_3 + 3H_2SO_4 \longrightarrow Al_2(SO_4)_3 + 3H_2O\\ (3)\quad Al_2(SO_4)_3 + 3NH_3 +3H_2O\longrightarrow 2Al(OH)_3\downarrow + 3(NH_4)_2SO_4\\ (4)\quad Al(OH)_3 + 3HCl \longrightarrow 3AlCl_3 + 3H_2O\\ (5)\quad AlCl_3 + 3NaOH \longrightarrow Al(OH)_3 \downarrow + 3NaCl\\ (6)\quad 2Al(OH)_3 \xrightarrow{\quad t^\circ \quad}Al_2O_3 + 3H_2O\\ (7)\quad 2Al_2O_3 \xrightarrow[900^\circ]{\text{điện phân nóng chảy}}4Al + 3O_2\uparrow\\ (8)\quad 2Al + 2NaOH + 2H_2O \xrightarrow{\quad t^\circ\quad} 2NaAlO_2 + 3H_2\uparrow\\ (9)\quad NaAlO_2 \nrightarrow Ba(AlO_2)_2 \end{array}$
1. 3Fe + 2$O_{2}$ → $Fe_{3}$O_{4}$
2. 8HCl + $Fe_{3}$O$_{4}$ → $FeCl_{2}$ + 4$H_{2}$O + 2$FeCl_{3}$
3. Fe + 2$FeCl_{3}$ → 2$FeCl_{2}$ + $FeCl_{2}$
4. $FeCl_{2}$ + 2NaOH → 2NaCl + Fe($OH)_{2}$
5. 2$H_{2}$O + $O_{2}$ + 4Fe($OH)_{2}$ → 4Fe($OH)_{3}$
6. 2Fe($OH)_{3}$ → $Fe_{2}$$O_{3}$ + 3$H_{2}$O
7.
8. 4Al + 3$O_{2}$ → 2$Al_{2}$$O_{3}$
9. $Al_{2}$$O_{3}$ + 3$H_{2}$$SO_{4}$ → $Al_{2}$($SO_{4}$)$_{3}$ + 3$H_{2}$O
10. $Al_{2}$($SO_{4}$)$_{3}$ + 6NaOH → 2Al$(OH)_{3}$ + 3$Na_{2}$$SO_{4}$
11. Al$(OH)_{3}$ + 3HCl → $AlCl_{3}$
12.$AlCl_{3}$ + 3NaOH → Al$(OH)_{3}$
13. 2Al$(OH)_{3}$ → $Al_{2}$$O_{3}$ + 3$H_{2}$O + 3NaCl + 3$H_{2}$O
14. 2$Al_{}$$O_{3}$ → 4Al + 3$O_{2}$↑
15. 2Al + 2$H_{2}$O + 2NaOH → 3$H_{2}$ + 2$NaAlO_{2}$
16. 3Ba($NO_{3}$)$_{2}$ + 10NaOH + 16Al + 4$H_{2}$O → 6$NH_{3}$ + 10Na$AlO_{2}$ + 3Ba($AlO_{2}$)$_{2}$ .