Hoàn thành pt $C_3H_6 \to A$ $A+2NaOH \to B \to C \to D $ $D+2NaOH \to E$ $E+2NaOH \to H_2$ 24/07/2021 Bởi Delilah Hoàn thành pt $C_3H_6 \to A$ $A+2NaOH \to B \to C \to D $ $D+2NaOH \to E$ $E+2NaOH \to H_2$
(Sửa: $E+2NaOH\to CH_4$) $C_3H_6$: xiclopropan $A: CH_2Cl-CH_2-CH_2Cl$ $B: CH_2OH-CH_2-CH_2OH$ $C: OHC-CH_2-CHO$ $D: HOOC-CH_2-COOH$ $E: NaOOC-CH_2-COONa$ PTHH: $C_3H_6+Cl_2\to ClCH_2-CH_2-CH_2Cl$ $ClCH_2-CH_2-CH_2Cl+2NaOH\xrightarrow{{t^o}} HOCH_2-CH_2-CH_2OH$ $HOCH_2-CH_2-CH_2OH+2CuO\xrightarrow{{t^o}} OHCCH_2CHO+2Cu+2H_2O$ $OHC-CH_2-CHO+2Br_2+2H_2O\to HOOC-CH_2-COOH+4HBr$ $HOOC-CH_2-COOH+2NaOH\to NaOOCCH_2COONa+2H_2O$ $NaOOCCH_2COONa+2NaOH\xrightarrow{{CaO, t^o}} 2Na_2CO_3+CH_4$ Bình luận
(Sửa: $E+2NaOH\to CH_4$)
$C_3H_6$: xiclopropan
$A: CH_2Cl-CH_2-CH_2Cl$
$B: CH_2OH-CH_2-CH_2OH$
$C: OHC-CH_2-CHO$
$D: HOOC-CH_2-COOH$
$E: NaOOC-CH_2-COONa$
PTHH:
$C_3H_6+Cl_2\to ClCH_2-CH_2-CH_2Cl$
$ClCH_2-CH_2-CH_2Cl+2NaOH\xrightarrow{{t^o}} HOCH_2-CH_2-CH_2OH$
$HOCH_2-CH_2-CH_2OH+2CuO\xrightarrow{{t^o}} OHCCH_2CHO+2Cu+2H_2O$
$OHC-CH_2-CHO+2Br_2+2H_2O\to HOOC-CH_2-COOH+4HBr$
$HOOC-CH_2-COOH+2NaOH\to NaOOCCH_2COONa+2H_2O$
$NaOOCCH_2COONa+2NaOH\xrightarrow{{CaO, t^o}} 2Na_2CO_3+CH_4$