Hoàn thành pt sau: $A(C_3H_6O_2) \buildrel{{+NaOH}}\over\longrightarrow A1 ⇆ A2 \to A3$ $A3+HCl \to A5$ $A3+KOH \to A4$

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1. $A_1: HCOONa$

   $A_2: HCOOH$

   $A_3: (NH_4)_2CO_3$

   $A_5: CO_2$

   $A_4: NH_3$

   PTHH:

   $HCOOC_2H_5+NaOH\xrightarrow{{t^o}} HCOONa+C_2H_5OH$

   $HCOONa+HCl\to HCOOH+NaCl$

   $HCOOH+NaOH\to HCOONa+H_2O$

   $HCOOH+2AgNO_3+4NH_3+H_2O\to (NH_4)_2CO_3+2Ag+2NH_4NO_3$   

   $(NH_4)_2CO_3+2HCl\to 2NH_4Cl+CO_2+H_2O$

   $(NH_4)_2CO_3+2KOH\to K_2CO_3+2NH_3+2H_2O$

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