I x-2/3I+3/5=1 và 3/5 (2/3.x +1/3)^2 =4/9 01/07/2021 Bởi Sarah I x-2/3I+3/5=1 và 3/5 (2/3.x +1/3)^2 =4/9
`|x – 2/3| + 3/5 = 1 3/5` `=> |x – 2/3| + 3/5 = 8/5` `=> |x – 2/3| = 8/5 – 3/5` `=> |x – 2/3| = 1` `=> x – 2/3 = 1`hoặc`-1` `TH1 : x – 2/3 = 1 => x = 1 + 2/3 = 1 2/3 = 5/3.` `TH2 : x – 2/3 = -1 => x = -1 + 2/3 = -3/3 + 2/3 = -1/3.` `(2/3 x + 1/3)^2 = 4/9` `=> (2/3 x + 1/3)^2 – (2/3)^2` `=> 2/3 x + 1/3 = 2/3` `=> 2/3 x = 2/3 – 1/3` `=> 2/3 x = 1/3` `=> x = 1/3 : 2/3` `=> x = 1/3 . 3/2` `=> x = 1/2.` Bình luận
@Bơ `| x-2/3|+3/5=1{ 3}/5` `| x-2/3|+3/5=8/5` `| x-2/3|=8/5 -3/5` `| x-2/3|=1` `x-2/3=1 ` hay` x-2/3= -1` `x=1+2/3` hay `x=-1+2/3` `x=5/3` hay `x=-1/3` `(2/3.x +1/3)^2 =4/9` `(2/3.x +1/3)^2 = ( 2/3)^2` `2/3.x+1/3=2/3` hay `2/3.x+1/3=-2/3` `2/3.x=2/3 – 1/3` hay `2/3.x=-2/3 – 1/3` `2/3.x = 1/3` hay ` 2/3.x=-1` `x=1/3 : 2/3` hay `x=-1:2/3` `x=1/2` hay ` x=-3/2` Bình luận
`|x – 2/3| + 3/5 = 1 3/5`
`=> |x – 2/3| + 3/5 = 8/5`
`=> |x – 2/3| = 8/5 – 3/5`
`=> |x – 2/3| = 1`
`=> x – 2/3 = 1`hoặc`-1`
`TH1 : x – 2/3 = 1 => x = 1 + 2/3 = 1 2/3 = 5/3.`
`TH2 : x – 2/3 = -1 => x = -1 + 2/3 = -3/3 + 2/3 = -1/3.`
`(2/3 x + 1/3)^2 = 4/9`
`=> (2/3 x + 1/3)^2 – (2/3)^2`
`=> 2/3 x + 1/3 = 2/3`
`=> 2/3 x = 2/3 – 1/3`
`=> 2/3 x = 1/3`
`=> x = 1/3 : 2/3`
`=> x = 1/3 . 3/2`
`=> x = 1/2.`
@Bơ
`| x-2/3|+3/5=1{ 3}/5`
`| x-2/3|+3/5=8/5`
`| x-2/3|=8/5 -3/5`
`| x-2/3|=1`
`x-2/3=1 ` hay` x-2/3= -1`
`x=1+2/3` hay `x=-1+2/3`
`x=5/3` hay `x=-1/3`
`(2/3.x +1/3)^2 =4/9`
`(2/3.x +1/3)^2 = ( 2/3)^2`
`2/3.x+1/3=2/3` hay `2/3.x+1/3=-2/3`
`2/3.x=2/3 – 1/3` hay `2/3.x=-2/3 – 1/3`
`2/3.x = 1/3` hay ` 2/3.x=-1`
`x=1/3 : 2/3` hay `x=-1:2/3`
`x=1/2` hay ` x=-3/2`