Ix+2I=0 Ix-5I = I-7I Ix-3I=7 – (-2) (7-x) – ( 25 + 7 ) = -25 07/12/2021 Bởi Emery Ix+2I=0 Ix-5I = I-7I Ix-3I=7 – (-2) (7-x) – ( 25 + 7 ) = -25
$|x+2|=0$ $x+2=0$ $x=0-2$ $x=0+(-2)$ $x=-2$ $—-$ $|x-5|=|-7|$ $x-5=7$ $x=7+5$$x=12$ $—-$ $|x-3|=7-(-2)$ $x-3=7+2$ $x=9+3$ $x=12$ $—-$ $(7-x)-(25+7)=-25$ $[(−x)+7]−(25+7)=−25$ $[(−x)+7]−32=−25$ $(-x)+7-32=-25$ $(−x)−25=−25$ $(−x)−25+25=(−25)+25$ $-x=0$ $|-x|=|0|$ $x=0$ Bình luận
|x+2|=0 x+2=0 hoặc -(x+2)=0 x =-2 -x-2=0 -x =2 x=-2 |x-5|=|-7| |x-5|=7 x-5=7 hoặc -(x-5)=7 x =12 -x+5 =7 -x =2 x =-2 |x-3|=7-(-2) |x-3|=9 x-3 =9 hoặc -(x-3) =9 x =12 -x+3 =9 -x =6 x =-6 (7-x) – (25+7) =-25 7-x – 32 =-25 7-x = 7 -x =0 x =0 Bình luận
$|x+2|=0$
$x+2=0$
$x=0-2$
$x=0+(-2)$
$x=-2$
$—-$
$|x-5|=|-7|$
$x-5=7$
$x=7+5$
$x=12$
$—-$
$|x-3|=7-(-2)$
$x-3=7+2$
$x=9+3$
$x=12$
$—-$
$(7-x)-(25+7)=-25$
$[(−x)+7]−(25+7)=−25$
$[(−x)+7]−32=−25$
$(-x)+7-32=-25$
$(−x)−25=−25$
$(−x)−25+25=(−25)+25$
$-x=0$
$|-x|=|0|$
$x=0$
|x+2|=0
x+2=0 hoặc -(x+2)=0
x =-2 -x-2=0
-x =2
x=-2
|x-5|=|-7|
|x-5|=7
x-5=7 hoặc -(x-5)=7
x =12 -x+5 =7
-x =2
x =-2
|x-3|=7-(-2)
|x-3|=9
x-3 =9 hoặc -(x-3) =9
x =12 -x+3 =9
-x =6
x =-6
(7-x) – (25+7) =-25
7-x – 32 =-25
7-x = 7
-x =0
x =0