làm giùm mình C=(1+1/1.3).(1+1/2.4).(1+1/3.5)………..(1+1/2020.2022) giúp vs mọi người ơi thanks trước nha 18/09/2021 Bởi Alice làm giùm mình C=(1+1/1.3).(1+1/2.4).(1+1/3.5)………..(1+1/2020.2022) giúp vs mọi người ơi thanks trước nha
`C = (1+ 1/1.3)(1+1/2.4)(1+1/3.5)…..(1+1/2020.2022)` `C= 4/3 . 9/8 . 16/15…..408441/408440` `C= (4.9.16…408441)/(3.8.15….408440)` `C= (2.2.3.3.4.4……2021.2021)/(1.3.2.4.3.5….2020.2022)` `C=(2.3.4…2021)/(1.2.3.4….2020) . (2.3.4…2021)/(3.4.5….2022)` `C= 2021. 2/2022` `C= 2021/1011` Vậy `C= 2021/1011` Bình luận
Đáp án + giải thích bước giải : `C = (1 + 1/(1 . 3) ) (1 + 1/(2 . 4) ) (1 + 1/(3 . 5) ) …. (1 + 1/(2020 . 2022) )` `-> C = (1 + 1/3) (1 + 1/8) (1 + 1/15) …. (1 + 1/4084440)` `-> C = 4/3 . 9/8 . 16/15 …. 4084441/4084440` `-> C = (4 . 9 . 16 …. 4084441)/(3 . 8 . 15 … 4084440)` `-> C = (2 . 3 . 4)/(1 . 2 . 3 . 4 … 2020) . (2 . 3 . 4 … 2021)/(3 . 4 . 5 …. 2022)` `-> C = 2021 . 2/2022` `-> C = 2021/1011` Vậy `C = 2021/1011` Bình luận
`C = (1+ 1/1.3)(1+1/2.4)(1+1/3.5)…..(1+1/2020.2022)`
`C= 4/3 . 9/8 . 16/15…..408441/408440`
`C= (4.9.16…408441)/(3.8.15….408440)`
`C= (2.2.3.3.4.4……2021.2021)/(1.3.2.4.3.5….2020.2022)`
`C=(2.3.4…2021)/(1.2.3.4….2020) . (2.3.4…2021)/(3.4.5….2022)`
`C= 2021. 2/2022`
`C= 2021/1011`
Vậy `C= 2021/1011`
Đáp án + giải thích bước giải :
`C = (1 + 1/(1 . 3) ) (1 + 1/(2 . 4) ) (1 + 1/(3 . 5) ) …. (1 + 1/(2020 . 2022) )`
`-> C = (1 + 1/3) (1 + 1/8) (1 + 1/15) …. (1 + 1/4084440)`
`-> C = 4/3 . 9/8 . 16/15 …. 4084441/4084440`
`-> C = (4 . 9 . 16 …. 4084441)/(3 . 8 . 15 … 4084440)`
`-> C = (2 . 3 . 4)/(1 . 2 . 3 . 4 … 2020) . (2 . 3 . 4 … 2021)/(3 . 4 . 5 …. 2022)`
`-> C = 2021 . 2/2022`
`-> C = 2021/1011`
Vậy `C = 2021/1011`