làm tính chia 1)5(x-y)^5/2(x-y)^2 2)36(x-y)^3/2(x+y)^2 3)4(x+y-z)^5/12(x+y-z)^3 4)35(x-y-z)^7/7(x-y-z)^5 5)(8x^4x^3+x^2)/2x 6)(2x^4-x^3+3x^2)/(-1/3x^2

0 bình luận về “làm tính chia 1)5(x-y)^5/2(x-y)^2 2)36(x-y)^3/2(x+y)^2 3)4(x+y-z)^5/12(x+y-z)^3 4)35(x-y-z)^7/7(x-y-z)^5 5)(8x^4x^3+x^2)/2x 6)(2x^4-x^3+3x^2)/(-1/3x^2”

1. Đáp án:

    $1)\dfrac{5}{2}(x-y)^3\\
   2)
   18(x+y)\\
   3)
   \dfrac{1}{3}(x+y-z)^2\\
   4)
   5(x-y-z)^2\\
   5)
   \dfrac{1}{2}x(8x^5+1)\\
   6)
   -3x^2(2x^2-x+3)\\
   7)
   y(-3x^2y^3+2x-y)$

   Giải thích các bước giải:

    $1)\dfrac{5(x-y)^5}{2(x-y)^2}=\dfrac{5}{2}(x-y)^3\\
   2)
   \dfrac{36(x+y)^3}{2(x+y)^2}=18(x+y)\\
   3)
   \dfrac{4(x+y-z)^5}{12(x+y-z)^3}=\dfrac{1}{3}(x+y-z)^2\\
   4)
   \dfrac{35(x-y-x)^7}{7(x-y-z)^5}=5(x-y-z)^2\\
   5)
   \dfrac{8x^4x^3+x^2}{2x}\\
   =\dfrac{x^2(8x^5+1)}{2x}\\
   =\dfrac{1}{2}x(8x^5+1)\\
   6)
   \dfrac{2x^4-x^3+3x^2}{-\dfrac{1}{3}x^2}\\
   =\dfrac{x^2(2x^2-x+3)}{-\dfrac{1}{3}x^2}\\
   =-3x^2(2x^2-x+3)\\
   7)
   \dfrac{-18x^3y^5+12x^2y^2-6xy^3}{6xy}\\
   =\dfrac{6xy^2(-3x^2y^3+2x-y)}{6xy}\\
   =y(-3x^2y^3+2x-y)$

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