Toán lim x →1 $\frac{\sqrt{x+8-3}}{x^2+2x-3}$ giải hộ mik vs 07/09/2021 By Athena lim x →1 $\frac{\sqrt{x+8-3}}{x^2+2x-3}$ giải hộ mik vs
$lim_x→1$$\frac{\sqrt{x+8-3)}}{x^2+2x-3}$ Ta có: $f(x)$ $f(1)$ $lim_x→1$ $\frac{\sqrt{(x+8-3)-\sqrt{(1+8-3)}})}{x-1}$.$\frac{1}{x+3}$ = $f’$$(1)$.$\frac{1}{4}$ ⇒$\frac{1}{24}$ Trả lời
$lim_x→1$$\frac{\sqrt{x+8-3)}}{x^2+2x-3}$
Ta có: $f(x)$ $f(1)$
$lim_x→1$ $\frac{\sqrt{(x+8-3)-\sqrt{(1+8-3)}})}{x-1}$.$\frac{1}{x+3}$
= $f’$$(1)$.$\frac{1}{4}$
⇒$\frac{1}{24}$