Lim (x đến 2)căn 4x+1 trong căn ngoài căn -3 phần mũ 3+x-10 25/10/2021 Bởi Everleigh Lim (x đến 2)căn 4x+1 trong căn ngoài căn -3 phần mũ 3+x-10
$\lim\limits_{x\to 2}\dfrac{ \sqrt{4x+1}-3}{x^3+x-10}$ $=\lim\limits_{x\to 2}\dfrac{4x+1-9}{(\sqrt{4x+1}+3)(x-2)(x^2+2x+5) }$ $=\lim\limits_{x\to 2}\dfrac{4}{(\sqrt{4x+1}+3)(x^2+2x+5)}$ $=\dfrac{4}{(\sqrt{4.2+1}+3)(2^2+2.2+5)}$ $=\dfrac{2}{39}$ Bình luận
$\lim\limits_{x\to 2}\dfrac{ \sqrt{4x+1}-3}{x^3+x-10}$
$=\lim\limits_{x\to 2}\dfrac{4x+1-9}{(\sqrt{4x+1}+3)(x-2)(x^2+2x+5) }$
$=\lim\limits_{x\to 2}\dfrac{4}{(\sqrt{4x+1}+3)(x^2+2x+5)}$
$=\dfrac{4}{(\sqrt{4.2+1}+3)(2^2+2.2+5)}$
$=\dfrac{2}{39}$