M=( 3+x/x-3 + 18/9-x^2 + x-3/x+3 ) : ( 1 – x+1/x+3 )

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1. Đáp án:

   `M=((x+3)/(x-3)+18/(9-x^2)+(x-3)/(x+3)):(1-(x+1)/(x+3))`

   `=>M=(((x+3)^2-18+(x-3)^2)/(x^2-9)):((x^2-9-(x+1)(x-3))/(x^2-9))`

   `=>M=(2x^2)/(x^2-9) . (x^2-9)/(2x-6)`

   `=>M=(2x^2)/(2(x-3))=(x^2)/(x-3)`

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2. `#Kenshiro`

   `⇒ M = ( (3+x)/(x-3) – 18/(9-x^2) + (x-3)/(x+3) ) : ( 1 – (x+1)/(x+3) )`

   `⇒ M = ( ((x+3)^2)/(x^2-9) – 18/(9-x^2) + ((x-3)^2)/(x^2-9) ) : 2/(x+3)`

   `⇒ M = ((x^2+6x+9-18+x^2-6x+9)/(x^2-9) ) xx ((x^2-9)/(2.(x-3)))`

   `⇒ M = (2x^2)/(x^2-9) xx (x^2-9)/(2.(x-3))`

   `⇒ M = (x^2)/(x-3)`

    

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