mn giải hộ mk bài này vs: x-2/2018+x-1/2019=x-2019/1-x-2018/2

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1. Đáp án: x=2020

    

   Giải thích các bước giải:

   $\begin{array}{l}
   \frac{{x – 2}}{{2018}} + \frac{{x – 1}}{{2019}} = \frac{{x – 2019}}{1} + \frac{{x – 2018}}{2}\\
    \Rightarrow \frac{{x – 2}}{{2018}} – 1 + \frac{{x – 1}}{{2019}} – 1 = \frac{{x – 2019}}{1} – 1 + \frac{{x – 2018}}{2} – 1\\
    \Rightarrow \frac{{x – 2 – 2018}}{{2018}} + \frac{{x – 1 – 2019}}{{2019}} = \frac{{x – 2019 – 1}}{1} + \frac{{x – 2018 – 2}}{2}\\
    \Rightarrow \frac{{x – 2020}}{{2018}} + \frac{{x – 2020}}{{2019}} = \frac{{x – 2020}}{1} + \frac{{x – 2020}}{2}\\
    \Rightarrow \left( {x – 2020} \right).\left( {\frac{1}{{2018}} + \frac{1}{{2019}} – \frac{1}{1} – \frac{1}{2}} \right) = 0\\
    \Rightarrow x = 2020
   \end{array}$

   Vậy x=2020

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