Mong giúp
5, 5×√(-1/5)^2
6, √(3+√5)^2
7, √(5-√5)^2
8, 3√(-1,5)^2-4√(-0,5)^2
9, 4×√(-3)^6+5×√(-2)^4
10, √(4-√11)^2+√11
11, √(√8-7)^2 – √8
Mong giúp
5, 5×√(-1/5)^2
6, √(3+√5)^2
7, √(5-√5)^2
8, 3√(-1,5)^2-4√(-0,5)^2
9, 4×√(-3)^6+5×√(-2)^4
10, √(4-√11)^2+√11
11, √(√8-7)^2 – √8
Câu 5:
`5*\sqrt{(-1/5)^2}=5*|-1/5|=5*1/5=1`
Câu 6:
`\sqrt{(3+\sqrt{5})^2}=|3+\sqrt{5}|=3+\sqrt{5}`
Câu 7:
`\sqrt{(5-\sqrt{5})^2}=|5-\sqrt{5}|=5-\sqrt{5}`
Câu 8:
`3\sqrt{(-1,5)^2}-4\sqrt{(-0,5)^2}=3|-1,5|-4|-0,5|`
`=3*1,5-4*0,5=4,5+2=2,5`
Câu 9:
`4\sqrt{(-3)^6}+5\sqrt{(-2)^4}=4\sqrt{[(-3)^3]^2}+5\sqrt{[(-2)^2]^2`
`=4|(-3)^3|+5|(-2)^2|=4*27+5*4=128`
Câu 10:
`\sqrt{(4-\sqrt{11})^2}+\sqrt{11}=|4-\sqrt{11}|+\sqrt{11}=4-\sqrt{11}+\sqrt{11}=4`
Câu 11:
`\sqrt{(\sqrt{8}-7)^2}-\sqrt{8}=|\sqrt{8}-7|-\sqrt{8}=-\sqrt{8}+7-\sqrt{8}=7-4\sqrt{2}`