Toán n, $\frac{22}{15}$.x + $\frac{1}{3}$ = |$\frac{-2}{3}$ + $\frac{1}{5}$ | 07/12/2021 By Savannah n, $\frac{22}{15}$.x + $\frac{1}{3}$ = |$\frac{-2}{3}$ + $\frac{1}{5}$ |
$\frac{22}{15}$ . x + $\frac{1}{3}$ = |$\frac{-2}{3}$ + $\frac{1}{5}$| $\frac{22}{15}$ . x + $\frac{1}{3}$ = |$\frac{-7}{15}$| $\frac{22}{15}$ . x + $\frac{1}{3}$ = $\frac{7}{15}$ $\frac{22}{15}$ . x = $\frac{7}{15}$ – $\frac{1}{3}$ $\frac{22}{15}$ . x = $\frac{2}{15}$ x = $\frac{2}{15}$ : $\frac{22}{15}$ x = $\frac{1}{11}$ Trả lời
Đáp án: $\frac{22}{15}$.x+$\frac{1}{3}$=| $\frac{-2}{3}$+$\frac{1}{5}$| ⇒ $\frac{22}{15}$.x+$\frac{1}{3}$=|$\frac{-7}{15}$| ⇒ $\frac{22}{15}$.x+$\frac{1}{3}$=$\frac{7}{15}$ ⇔ $\frac{22}{15}$.x=$\frac{7}{15}$-$\frac{1}{3}$ ⇔ $\frac{22}{15}$.x=$\frac{2}{15}$ ⇔ x=$\frac{2}{15}$÷$\frac{22}{15}$ ⇔ x=$\frac{1}{11}$ Vậy x=$\frac{1}{11}$ Trả lời
$\frac{22}{15}$ . x + $\frac{1}{3}$ = |$\frac{-2}{3}$ + $\frac{1}{5}$|
$\frac{22}{15}$ . x + $\frac{1}{3}$ = |$\frac{-7}{15}$|
$\frac{22}{15}$ . x + $\frac{1}{3}$ = $\frac{7}{15}$
$\frac{22}{15}$ . x = $\frac{7}{15}$ – $\frac{1}{3}$
$\frac{22}{15}$ . x = $\frac{2}{15}$
x = $\frac{2}{15}$ : $\frac{22}{15}$
x = $\frac{1}{11}$
Đáp án:
$\frac{22}{15}$.x+$\frac{1}{3}$=| $\frac{-2}{3}$+$\frac{1}{5}$|
⇒ $\frac{22}{15}$.x+$\frac{1}{3}$=|$\frac{-7}{15}$|
⇒ $\frac{22}{15}$.x+$\frac{1}{3}$=$\frac{7}{15}$
⇔ $\frac{22}{15}$.x=$\frac{7}{15}$-$\frac{1}{3}$
⇔ $\frac{22}{15}$.x=$\frac{2}{15}$
⇔ x=$\frac{2}{15}$÷$\frac{22}{15}$
⇔ x=$\frac{1}{11}$
Vậy x=$\frac{1}{11}$