P(x)=3x-2/3x^2+x^3+2x+4x^2-5/4 Q(x)=-x^3+2/3x^2-5x+7 tính P(x)-Q(x) P(x0+Q(x) 26/09/2021 Bởi Sarah P(x)=3x-2/3x^2+x^3+2x+4x^2-5/4 Q(x)=-x^3+2/3x^2-5x+7 tính P(x)-Q(x) P(x0+Q(x)
`Thu` `gọn` `:` `P ( x ) = 3x – 2/3x^2 + x^3 + 2x + 4x^2 – 5/4` `= ( 3x + 2x ) + ( – 2/3x^2 + 4x^2 ) + x^3 – 5/4` `= 5x + 10/3x^2 + x^3 – 5/4` `Tính“ P ( x ) – Q ( x )` `P ( x ) = 5x + 10/3x^2 + x^3 – 5/4` `-` `Q ( x ) = 5x + 2/3x^2 – x^3 + 7` `= 8/3x^2 + 2x^3 – 33/4` `Tính` `P ( x ) + Q ( x )` `P ( x ) = 5x + 10/3x^2 + x^3 – 5/4` `+` `Q ( x ) = 5x + 2/3x^2 – x^3 + 7` `= 10x + 12/3x^2 + 23/4` `HỌC` `TỐT` `NHA` `!` `#NOCOPY` Bình luận
Đáp án:
Giải thích các bước giải:
`Thu` `gọn` `:`
`P ( x ) = 3x – 2/3x^2 + x^3 + 2x + 4x^2 – 5/4`
`= ( 3x + 2x ) + ( – 2/3x^2 + 4x^2 ) + x^3 – 5/4`
`= 5x + 10/3x^2 + x^3 – 5/4`
`Tính“ P ( x ) – Q ( x )`
`P ( x ) = 5x + 10/3x^2 + x^3 – 5/4`
`-`
`Q ( x ) = 5x + 2/3x^2 – x^3 + 7`
`= 8/3x^2 + 2x^3 – 33/4`
`Tính` `P ( x ) + Q ( x )`
`P ( x ) = 5x + 10/3x^2 + x^3 – 5/4`
`+`
`Q ( x ) = 5x + 2/3x^2 – x^3 + 7`
`= 10x + 12/3x^2 + 23/4`
`HỌC` `TỐT` `NHA` `!`
`#NOCOPY`