P=a/căn a-1 -2a-căn a /a-căn a A.rút gọn B.tính giá trị cỉa p với a=3-căn 8 C.tìm a để p <0 03/08/2021 Bởi Cora P=a/căn a-1 -2a-căn a /a-căn a A.rút gọn B.tính giá trị cỉa p với a=3-căn 8 C.tìm a để p <0
Đáp án: $\begin{array}{l}P = \dfrac{a}{{\sqrt a – 1}} – \dfrac{{2a – \sqrt a }}{{a – \sqrt a }}\\a)Dkxd:a > 0;a \ne 1\\P = \dfrac{a}{{\sqrt a – 1}} – \dfrac{{\sqrt a \left( {2\sqrt a – 1} \right)}}{{\sqrt a \left( {\sqrt a – 1} \right)}}\\ = \dfrac{a}{{\sqrt a – 1}} – \dfrac{{2\sqrt a – 1}}{{\sqrt a – 1}}\\ = \dfrac{{a – 2\sqrt a + 1}}{{\sqrt a – 1}}\\ = \dfrac{{{{\left( {\sqrt a – 1} \right)}^2}}}{{\sqrt a – 1}}\\ = \sqrt a – 1\\b)a = 3 – \sqrt 8 \left( {tmdk} \right)\\ = 3 – 2\sqrt 2 \\ = {\left( {\sqrt 2 – 1} \right)^2}\\ \Rightarrow \sqrt a = \sqrt 2 – 1\\ \Rightarrow P = \sqrt a – 1 = \sqrt 2 – 1 – 1 = \sqrt 2 – 2\\c)P < 0\\ \Rightarrow \sqrt a – 1 < 0\\ \Rightarrow \sqrt a < 1\\ \Rightarrow a < 1\\Vay\,0 < a < 1\end{array}$ Bình luận
Đáp án:
$\begin{array}{l}
P = \dfrac{a}{{\sqrt a – 1}} – \dfrac{{2a – \sqrt a }}{{a – \sqrt a }}\\
a)Dkxd:a > 0;a \ne 1\\
P = \dfrac{a}{{\sqrt a – 1}} – \dfrac{{\sqrt a \left( {2\sqrt a – 1} \right)}}{{\sqrt a \left( {\sqrt a – 1} \right)}}\\
= \dfrac{a}{{\sqrt a – 1}} – \dfrac{{2\sqrt a – 1}}{{\sqrt a – 1}}\\
= \dfrac{{a – 2\sqrt a + 1}}{{\sqrt a – 1}}\\
= \dfrac{{{{\left( {\sqrt a – 1} \right)}^2}}}{{\sqrt a – 1}}\\
= \sqrt a – 1\\
b)a = 3 – \sqrt 8 \left( {tmdk} \right)\\
= 3 – 2\sqrt 2 \\
= {\left( {\sqrt 2 – 1} \right)^2}\\
\Rightarrow \sqrt a = \sqrt 2 – 1\\
\Rightarrow P = \sqrt a – 1 = \sqrt 2 – 1 – 1 = \sqrt 2 – 2\\
c)P < 0\\
\Rightarrow \sqrt a – 1 < 0\\
\Rightarrow \sqrt a < 1\\
\Rightarrow a < 1\\
Vay\,0 < a < 1
\end{array}$