Phân tích đa thức thành nhân tử (4x^2 -7x-50)^2-16x^4-56x^3-49x^2 03/07/2021 Bởi Kylie Phân tích đa thức thành nhân tử (4x^2 -7x-50)^2-16x^4-56x^3-49x^2
Đáp án: `(4x^2-7x-50)^2-16x^4-56x^3-49x^2` `=(4x^2-7x-50)^2-x^2(16x^2+2.4x.7+49)` `=(4x^2-7x-50)^2-x^2(4x+7)^2` `=[(4x^2-7x-50)-x(4x+7)][(4x^2-7x-50)+x(4x+7)]` `=(4x^2-7x-50-4x^2-7x)(4x^2-7x-50+4x^2+7x)` `=(-14x-50)(8x^2-50)` `=-4(7x+25)(4x^2-25)` `=-4(7x+25)(2x-5)(2x+5)` Bình luận
`(4x^2–7x–50)^2–16x^4–56x^3–49x^2` `=(4x^2–7x–50)^2–x^2(4x+7)^2` `=[(4x^2–7x–50)–x(4x+7)] . [(4x^2–7x–50)+x(4x+7)]` `=(4x^2–7x–50–4x^2–7x) (4x^2–7x–50+4x2+7x)` `=(–14x–50)(8x^2–50)` `=(–4)(7x+25)(4x^2–25)` `=(–4)(7x+25)(2x–5)(2x+5)` Bình luận
Đáp án:
`(4x^2-7x-50)^2-16x^4-56x^3-49x^2`
`=(4x^2-7x-50)^2-x^2(16x^2+2.4x.7+49)`
`=(4x^2-7x-50)^2-x^2(4x+7)^2`
`=[(4x^2-7x-50)-x(4x+7)][(4x^2-7x-50)+x(4x+7)]`
`=(4x^2-7x-50-4x^2-7x)(4x^2-7x-50+4x^2+7x)`
`=(-14x-50)(8x^2-50)`
`=-4(7x+25)(4x^2-25)`
`=-4(7x+25)(2x-5)(2x+5)`
`(4x^2–7x–50)^2–16x^4–56x^3–49x^2`
`=(4x^2–7x–50)^2–x^2(4x+7)^2`
`=[(4x^2–7x–50)–x(4x+7)] . [(4x^2–7x–50)+x(4x+7)]`
`=(4x^2–7x–50–4x^2–7x) (4x^2–7x–50+4x2+7x)`
`=(–14x–50)(8x^2–50)`
`=(–4)(7x+25)(4x^2–25)`
`=(–4)(7x+25)(2x–5)(2x+5)`