phân tích đa thức thành nhân tử a) x²-y²-2x+2y b) 2x+2y-x²-xy c) 3a²-6ab+3b²-12c² d) x²-25+y²+2xy e) a²+2ab+b²-ac-bc 26/10/2021 Bởi Valerie phân tích đa thức thành nhân tử a) x²-y²-2x+2y b) 2x+2y-x²-xy c) 3a²-6ab+3b²-12c² d) x²-25+y²+2xy e) a²+2ab+b²-ac-bc
a) $x^2-y^2-2x+2y$ $=(x-y)(x+y)-2(x-y)$ $=(x-y)(x+y-2)$ b) $2x+2y-x^2-xy$ $=2(x+y)-x(x+y)$ $=(x+y)(2-x)$ c) $3a^2-6ab+3b^2-12c^2$ $=3.(a^2-2ab+b^2)-4c^2$ $=3.[(a-b)^2-(2c)^2]$ $=3.(a-b-2c).(a-b+2c)$ d) $x^2-25+y^2+2xy$ $=(x^2+2xy+y^2)-25$ $=(x+y)^2-25$ $=(x+y+5)(x+y-5)$ e) $a^2+2ab+b^2-ac-bc$ $=(a^2+2ab+b^2)-c.(a+b)$ $=(a+b)^2-c.(a+b)$ $=(a+b)(a+b-c)$ Bình luận
$a) x²-y²-2x+2y$ $= (x+y)(x-y)-2(x-y)$ $= (x-y)(x+y-2)$ $b) 2x+2y-x²-xy$ $= 2(x+y)-x(x+y)$ $= (x+y)(2-x)$ $c) 3a²-6ab+3b²-12c²$ $= 3(a²-2ab+b²-4c²)$ $= 3[(a-b)²-(2c)²]$ $= 3(a-b+2c)(a-b-2c)$ $d) x²-25+y²+2xy$ $= x²+2xy+y²-25$ $= (x+y)²-5²$ $= (x+y+5)(x+y-5)$ $e) a²+2ab+b²-ac-bc$ $= (a+b)²-c(a+b)$ $= (a+b)(a+b-c)$ Bình luận
a) $x^2-y^2-2x+2y$
$=(x-y)(x+y)-2(x-y)$
$=(x-y)(x+y-2)$
b) $2x+2y-x^2-xy$
$=2(x+y)-x(x+y)$
$=(x+y)(2-x)$
c) $3a^2-6ab+3b^2-12c^2$
$=3.(a^2-2ab+b^2)-4c^2$
$=3.[(a-b)^2-(2c)^2]$
$=3.(a-b-2c).(a-b+2c)$
d) $x^2-25+y^2+2xy$
$=(x^2+2xy+y^2)-25$
$=(x+y)^2-25$
$=(x+y+5)(x+y-5)$
e) $a^2+2ab+b^2-ac-bc$
$=(a^2+2ab+b^2)-c.(a+b)$
$=(a+b)^2-c.(a+b)$
$=(a+b)(a+b-c)$
$a) x²-y²-2x+2y$
$= (x+y)(x-y)-2(x-y)$
$= (x-y)(x+y-2)$
$b) 2x+2y-x²-xy$
$= 2(x+y)-x(x+y)$
$= (x+y)(2-x)$
$c) 3a²-6ab+3b²-12c²$
$= 3(a²-2ab+b²-4c²)$
$= 3[(a-b)²-(2c)²]$
$= 3(a-b+2c)(a-b-2c)$
$d) x²-25+y²+2xy$
$= x²+2xy+y²-25$
$= (x+y)²-5²$
$= (x+y+5)(x+y-5)$
$e) a²+2ab+b²-ac-bc$
$= (a+b)²-c(a+b)$
$= (a+b)(a+b-c)$