phân tích thành nhân tử (x^2-1)^2 – 3 (x-1) +2

Giải thích các bước giải:

(x²-1)² – 3 (x-1) +2

= (x²−1²)²−3(x−1)+2

= [(x+1)(x−1)]²−3(x−1)+2

= (x+1)²(x−1)²−3(x−1)+2

= (x²+2x+1)(x−1)²−3(x−1)+2

= (x²+2x+1)(x²−2x+1)−3(x−1)+2

= x²(x²−2x+1)+2x(x²−2x+1)+x²−2x+1−3(x−1)+2

= $x^{4}$−2x³+x²+2x(x²−2x+1)+x²−2x+1−3(x−1)+2

= $x^{4}$−2x³+x²+2x³−4x²+2x+x²−2x+1−(3x−3)+2

= $x^{4}$−2x³+x²+2x³−4x²+2x+x²−2x+1−3x+3+2

= $x^{4}$+(−2x³+2x³)+(x²−4x²+x²)+(2²−2x−3x)+(1+3+2)

= $x^{4}$−2x²−3x+6

xin hay nhất! :)))