PTĐTTNT 1,$x^{4}$+2002 $x^{2}$ -2001x+2002 2,$x^{4}$+2005 $x^{2}$ -2004x+2005 làm đầy đủ mik vote 5 sao

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1. Đáp án:

    1) `(x² -x +1).(x² +x +2002)`

   2) `(x² -x +1).(x² +x +2005)`

   Giải thích các bước giải:

   1) `x^4 +2002x² -2001x +2002`

   `= x^4 +2002x² +x -2002x +2002`

   `= (x^4 +x) + (2002x² -2002x +2002)`

   `= x.(x³ +1) + 2002.(x² -x +1)`

   `= x.(x +1).(x² -x +1) +2002.(x² -x +1)`

   `= (x² -x +1).[x.(x +1) +2002]`

   `= (x² -x +1).(x² +x +2002)`

   2) `x^4 +2005x² -2004x +2005`

   `= x^4 +2005x² +x -2005x +2005`

   `= (x^4 +x) + (2005x² -2005x +2005)`

   `= x.(x³ +1) + 2005.(x² -x +1)`

   `= x.(x +1).(x² -x +1) +2005.(x² -x +1)`

   `= (x² -x +1).[x.(x +1) +2005]`

   `= (x² -x +1).(x² +x +2005)`

   Trả lời

2. `1) x^4 + 2002x^2 – 2001x + 2002.`

   `=x^4 + 2002x^2 + x – 2002x + 2002`

   `= (x^4 + x ) + (2002x^2 – 2002x + 2002)`

    `= x(x^3+1) + 2002(x^2 – x + 1)`

   `= x(x+1)(x^2-x+1) + 2002(x^2 – x + 1)`

   `= (x^2-x+1)[x(x+1)+2002]`

   `= (x^2-x+1)(x^2+x+2002).`

   `2) x^4 + 2005x^2 – 2004x + 2005.`

   `=x^4 + 2005x^2 + x – 2005x + 2005`

   `= (x^4 + x ) + (2005x^2 – 2005x + 2005)`

    `= x(x^3+1) + 2005(x^2 – x + 1)`

   `= x(x+1)(x^2-x+1) + 2005(x^2 – x + 1)`

   `= (x^2-x+1)[x(x+1)+2005]`

   `= (x^2-x+1)(x^2+x+2005).`

   Trả lời