Ptđttnt x⁵+64 Thanks you ch vjd jgfjrjfdjfjf 16/11/2021 Bởi Eloise Ptđttnt x⁵+64 Thanks you ch vjd jgfjrjfdjfjf
`x^5+64` `=[(sqrt(x^5))^2+2*sqrt(x^5)*8+8^2]-16sqrt(x^5)` `=(sqrt(x^5)+8)^2-(4`$\sqrt[4]{x^5})^2$ `=(\sqrt[x^5]+8+`$4\sqrt[4]{x^5}\bigg)$`(sqrt(x^5)+8-` $\sqrt[4]{x^5}\bigg)$ Bình luận
Đáp án: `=(\sqrt{x^5}-4root{4}{x^5}+8)(\sqrt{x^5}+4root{4}{x^5}+8)` Giải thích các bước giải: `x^5+64` `=x^5+16\sqrt{x^5}+64-16\sqrt{x^5}(x>=0)` `=(\sqrt{x^5}+8)^2-(4root{4}{x^5})^2` `=(\sqrt{x^5}-4root{4}{x^5}+8)(\sqrt{x^5}+4root{4}{x^5}+8)` Bình luận
`x^5+64`
`=[(sqrt(x^5))^2+2*sqrt(x^5)*8+8^2]-16sqrt(x^5)`
`=(sqrt(x^5)+8)^2-(4`$\sqrt[4]{x^5})^2$
`=(\sqrt[x^5]+8+`$4\sqrt[4]{x^5}\bigg)$`(sqrt(x^5)+8-` $\sqrt[4]{x^5}\bigg)$
Đáp án:
`=(\sqrt{x^5}-4root{4}{x^5}+8)(\sqrt{x^5}+4root{4}{x^5}+8)`
Giải thích các bước giải:
`x^5+64`
`=x^5+16\sqrt{x^5}+64-16\sqrt{x^5}(x>=0)`
`=(\sqrt{x^5}+8)^2-(4root{4}{x^5})^2`
`=(\sqrt{x^5}-4root{4}{x^5}+8)(\sqrt{x^5}+4root{4}{x^5}+8)`