Toán PTĐTTNT x(x-y)^3 -y(y-x)^2 -y^2(x-y) làm ơn hãy giúp mình 02/07/2021 By Abigail PTĐTTNT x(x-y)^3 -y(y-x)^2 -y^2(x-y) làm ơn hãy giúp mình
x(x-y)^3 – y(y-x)^2 – y^2(x-y) =x(x-y)^3 -y(x-y)^2 – y^2(x-y) =(x-y)[x(x-y)^2-y-y^2] =(x-y)(x^3 -2x^2y+xy^2-y-y^2) =(x-y)(x^3-2x^2y-y+x-1) mình ko chắc lắm nên bạn tham khảo thêm nha. Trả lời
$x(x-y)^3-y(y-x)^2-y^2(x-y)$ $=x(x-y)^3-y(x-y)^2-y^2(x-y)$ $=(x-y)[x(x-y)^2-y(x-y)-y^2-1]$ $=(x-y)[x(x^2-2xy+y^2)-xy+y^2-y^2-1]$ $=(x-y)[x^3-2x^2y+xy^2-xy+y^2-y^2-1]$ $=(x-y)(x^3-2x^2y+xy^2-xy-1)$ Trả lời
x(x-y)^3 – y(y-x)^2 – y^2(x-y)
=x(x-y)^3 -y(x-y)^2 – y^2(x-y)
=(x-y)[x(x-y)^2-y-y^2]
=(x-y)(x^3 -2x^2y+xy^2-y-y^2)
=(x-y)(x^3-2x^2y-y+x-1)
mình ko chắc lắm nên bạn tham khảo thêm nha.
$x(x-y)^3-y(y-x)^2-y^2(x-y)$
$=x(x-y)^3-y(x-y)^2-y^2(x-y)$
$=(x-y)[x(x-y)^2-y(x-y)-y^2-1]$
$=(x-y)[x(x^2-2xy+y^2)-xy+y^2-y^2-1]$
$=(x-y)[x^3-2x^2y+xy^2-xy+y^2-y^2-1]$
$=(x-y)(x^3-2x^2y+xy^2-xy-1)$