Q= (1/x-cănx – 1/cănx -1):(2/cănx -1) với x>0, x khác 1, x khác 4) 24/11/2021 Bởi Cora Q= (1/x-cănx – 1/cănx -1):(2/cănx -1) với x>0, x khác 1, x khác 4)
Đáp án: $\begin{array}{l}Dkxd:x > 0;x \ne 1;x \ne 4\\Q = \left( {\frac{1}{{x – \sqrt x }} – \frac{1}{{\sqrt x – 1}}} \right):\frac{2}{{\sqrt x – 1}}\\ = \left[ {\frac{1}{{\sqrt x \left( {\sqrt x – 1} \right)}} – \frac{1}{{\sqrt x – 1}}} \right].\frac{{\sqrt x – 1}}{2}\\ = \frac{{1 – \sqrt x }}{{\sqrt x \left( {\sqrt x – 1} \right)}}.\frac{{\sqrt x – 1}}{2}\\ = \frac{{1 – \sqrt x }}{{2\sqrt x }}\end{array}$ Bình luận
Đáp án:
$\begin{array}{l}
Dkxd:x > 0;x \ne 1;x \ne 4\\
Q = \left( {\frac{1}{{x – \sqrt x }} – \frac{1}{{\sqrt x – 1}}} \right):\frac{2}{{\sqrt x – 1}}\\
= \left[ {\frac{1}{{\sqrt x \left( {\sqrt x – 1} \right)}} – \frac{1}{{\sqrt x – 1}}} \right].\frac{{\sqrt x – 1}}{2}\\
= \frac{{1 – \sqrt x }}{{\sqrt x \left( {\sqrt x – 1} \right)}}.\frac{{\sqrt x – 1}}{2}\\
= \frac{{1 – \sqrt x }}{{2\sqrt x }}
\end{array}$