## Hứa 5 sao và ctlhn. Mary paid $287 for 2 handbags and 5 blouses. On average, a handbag cost$42 more than a blouse. How much did she pay for the 5 blo

Question

Hứa 5 sao và ctlhn. Mary paid $287 for 2 handbags and 5 blouses. On average, a handbag cost$42 more
than a blouse. How much did she pay for the 5 blouses?

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3 tháng 2021-09-24T21:36:09+00:00 2 Answers 4 views 0

## Answers ( )

1. $We have:2xhandbags+5xblouses=287$

$Handbag-Blouse=42=>Handbag=Blouse +42$

$We have:2x(blouse +42)+5blouses=287$

$=>2blouses+84+5blouses=287$

$=>7blouses=-287-84=203$

$=>1Blouse:203:7=29$

Therefore,the price of 5 blouses is computed as below: $29×5=145$

2. We have: 2 x handbags + 5 x blouses = 287 (1)

Handbag – Blouse = 42 => Handbag = Blouse + 42

We have: (1) ⇔ 2 x (blouse +42) + 5 blouses = 287

⇔ 2 blouses + 84 + 5 blouses = 287

⇔ 7 blouses = 287 – 84 = 203

⇔ 1 Blouse = 203 : 7 = 29

Therefore, the price of 5 blouses is computed as below:

29 x 5 = 145