Rut gon: a) (2x+3)^2-(x-5)^2-(x-1) (3x+2) b) 5x (x-6)-(3x+4 (3x-4)- 6x^2 c) (2x-4)^2-5x(2x+1)-(4x+1)^2 05/07/2021 Bởi Gabriella Rut gon: a) (2x+3)^2-(x-5)^2-(x-1) (3x+2) b) 5x (x-6)-(3x+4 (3x-4)- 6x^2 c) (2x-4)^2-5x(2x+1)-(4x+1)^2
Đáp án: Giải thích các bước giải: `a) (2x+3)^2-(x-5)^2-(x-1) (3x+2)` `=4x^2+12x+9-(x^2-10x+25)-(3x^2+2x-3x-2)` `=23x-11` `b) 5x (x-6)-(3x+4) (3x-4)- 6x^2 ` `=5x^2-30x-9x^2+16-6x^2` `=-10x^2-30x+16` `c) (2x-4)^2-5x(2x+1)-(4x+1)^2` `=4x^2-16x+16-(10x^2+5x)-(16x^2+8x+1)` `=-22x^2-29x+15` Bình luận
Đáp án:
Giải thích các bước giải:
`a) (2x+3)^2-(x-5)^2-(x-1) (3x+2)`
`=4x^2+12x+9-(x^2-10x+25)-(3x^2+2x-3x-2)`
`=23x-11`
`b) 5x (x-6)-(3x+4) (3x-4)- 6x^2 `
`=5x^2-30x-9x^2+16-6x^2`
`=-10x^2-30x+16`
`c) (2x-4)^2-5x(2x+1)-(4x+1)^2`
`=4x^2-16x+16-(10x^2+5x)-(16x^2+8x+1)`
`=-22x^2-29x+15`