Toán rút gọn biểu thức sau 2x(x-7)-(x+3)(x-2)-(x+4)(x-4) 09/07/2021 By Gianna rút gọn biểu thức sau 2x(x-7)-(x+3)(x-2)-(x+4)(x-4)
` 2x(x-7)-(x+3)(x-2)-(x+4)(x-4)` `=2x^2-14x-(x^2+x-6)-(x^2-16)` `=2x^2-x^2-x^2-14x-x+6+16` `=22-15x` Trả lời
` 2x(x-7)-(x+3)(x-2)-(x+4)(x-4)`
`=2x^2-14x-(x^2+x-6)-(x^2-16)`
`=2x^2-x^2-x^2-14x-x+6+16`
`=22-15x`
2x(x-7) – (x+3)(x-2) – (x+4)(x-4)
= 2x² – 14x – x² – x + 6 – x² + 16
= -15x + 22