rút gọn c c = ( 1/x ² + 1 – x + 1/x ∧4 -1) : x+ 1/ x ∧5 + x ∧4 -x -1 ( ai có avatar anime đẹp tui cho hay nhất ) 19/07/2021 Bởi Alaia rút gọn c c = ( 1/x ² + 1 – x + 1/x ∧4 -1) : x+ 1/ x ∧5 + x ∧4 -x -1 ( ai có avatar anime đẹp tui cho hay nhất )
$\rm C=(\dfrac{1}{x^2+1}-\dfrac{x+1}{x^4-1}):\dfrac{x+1}{x^5+x^4-x-1} \\C=(\dfrac{1}{x^2+1}-\dfrac{x+1}{(x^2+1)(x^2-1)}):\dfrac{x+1}{x^5+x^4-x-1}\\C=(\dfrac{x^2-1-(x+1)}{(x^2+1)(x^2-1)}:\dfrac{x+1}{x^5+x^4-x-1}\\C=(\dfrac{x^2-x-2}{(x^2+1)(x^2-1)}):\dfrac{x+1}{(x+1)^2(x-1)(x^2+1)} \\C=(\dfrac{(x+1)(x-2)}{(x^2+1)(x-1)(x+1)}).\dfrac{(x+1)^2(x-1)(x^2+1)}{x+1}\\C=(x-2)(x-1)\\C=x^2-x-2\\ Vậy \ C=x^2-x-2\\\rm $ Bình luận
`C = ( 1/(x^2 + 1) – (x + 1)/(x^4 -1)) : (x+ 1)/ (x^5 + x^4 -x -1)` ` = ((x^2 – 1)/(x^4 -1) – (x+1)/(x^4-1)) : (x+1)/(x^4 . (x+1) – (x+1)` ` = (x^2 – 1 – (x+1))/(x^4 -1) : (x+1)/((x^4 -1).(x+1))` ` = (x^2 – 1 – x – 1)/(x^4 – 1) : 1/(x^4 – 1)` ` = (x^2 – x – 2)/(x^4 – 1) . (x^4 – 1)` ` = x^2 – x – 2` Vậy `C = x^2 – x – 2` Bình luận
$\rm C=(\dfrac{1}{x^2+1}-\dfrac{x+1}{x^4-1}):\dfrac{x+1}{x^5+x^4-x-1} \\C=(\dfrac{1}{x^2+1}-\dfrac{x+1}{(x^2+1)(x^2-1)}):\dfrac{x+1}{x^5+x^4-x-1}\\C=(\dfrac{x^2-1-(x+1)}{(x^2+1)(x^2-1)}:\dfrac{x+1}{x^5+x^4-x-1}\\C=(\dfrac{x^2-x-2}{(x^2+1)(x^2-1)}):\dfrac{x+1}{(x+1)^2(x-1)(x^2+1)} \\C=(\dfrac{(x+1)(x-2)}{(x^2+1)(x-1)(x+1)}).\dfrac{(x+1)^2(x-1)(x^2+1)}{x+1}\\C=(x-2)(x-1)\\C=x^2-x-2\\ Vậy \ C=x^2-x-2\\\rm $
`C = ( 1/(x^2 + 1) – (x + 1)/(x^4 -1)) : (x+ 1)/ (x^5 + x^4 -x -1)`
` = ((x^2 – 1)/(x^4 -1) – (x+1)/(x^4-1)) : (x+1)/(x^4 . (x+1) – (x+1)`
` = (x^2 – 1 – (x+1))/(x^4 -1) : (x+1)/((x^4 -1).(x+1))`
` = (x^2 – 1 – x – 1)/(x^4 – 1) : 1/(x^4 – 1)`
` = (x^2 – x – 2)/(x^4 – 1) . (x^4 – 1)`
` = x^2 – x – 2`
Vậy `C = x^2 – x – 2`