Rút gọn P= $($$\frac{\sqrt{x}-1}{\sqrt{x}+1}$$-$$\frac{\sqrt{x}+1}{\sqrt{x}-1}$$)$.$($$\frac{1}{2\sqrt{x}}$$-$$\frac{\sqrt{x}}{2}$$)$$^{2}$

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1. $(\dfrac{\sqrt[]{x}-1}{\sqrt[]{x}+1}-\dfrac{\sqrt[]{x}+1}{\sqrt[]{x}-1}).(\dfrac{1}{2\sqrt[]{x}}-\dfrac{\sqrt[]{x}}{2})^2$

   $=\dfrac{(\sqrt[]{x}-1)^2-(\sqrt[]{x}+1)^2}{(\sqrt[]{x}-1)(\sqrt[]{x}+1)}.(\dfrac{1-x}{2\sqrt[]{x}})^2$

   $=\dfrac{-4\sqrt[]{x}}{(\sqrt[]{x}-1)(\sqrt[]{x}+1)}.\dfrac{[(\sqrt[]{x}-1)(\sqrt[]{x}+1)]^2}{4x}$

   $=\dfrac{1-x}{\sqrt[]{x}}$

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