S = 1 – 2 + 3 – 4. + 5 – 6 + … + 2001 – 2002 + 2003. 19/07/2021 Bởi Clara S = 1 – 2 + 3 – 4. + 5 – 6 + … + 2001 – 2002 + 2003.
Đáp án: S = 1 – 2 + 3 – 4. + 5 – 6 + … + 2001 – 2002 + 2003. = (1-2)+(3-4)+(5-6)+…+(2001-2002)+2003 = (-1) + (-1) + (-1) +…+ (-1) + 2003 = (-1) × 1001 + 2002 = -1002 Bình luận
$S = 1 – 2 + 3 – 4 + 5 – 6 + … + 2001 – 2002 + 2003$ $= (1-2) + (3-4) + (5-6) +…+ (2001 – 2002) + 2003$ $= -1 – 1 ….. – 1 + 2003$ $= -1 . 1001 + 2003$ $→ S = 1002$ Bình luận
Đáp án:
S = 1 – 2 + 3 – 4. + 5 – 6 + … + 2001 – 2002 + 2003.
= (1-2)+(3-4)+(5-6)+…+(2001-2002)+2003
= (-1) + (-1) + (-1) +…+ (-1) + 2003
= (-1) × 1001 + 2002
= -1002
$S = 1 – 2 + 3 – 4 + 5 – 6 + … + 2001 – 2002 + 2003$
$= (1-2) + (3-4) + (5-6) +…+ (2001 – 2002) + 2003$
$= -1 – 1 ….. – 1 + 2003$
$= -1 . 1001 + 2003$
$→ S = 1002$