So Sanh
a) $\frac{1}{4}$$\sqrt[]{82}$ va 6$\sqrt[]{\frac{1}{7}}$
b) $\sqrt[]{6}$ – 1 va 3
So Sanh a) $\frac{1}{4}$$\sqrt[]{82}$ va 6$\sqrt[]{\frac{1}{7}}$ b) $\sqrt[]{6}$ – 1 va 3
By Aubrey
By Aubrey
So Sanh
a) $\frac{1}{4}$$\sqrt[]{82}$ va 6$\sqrt[]{\frac{1}{7}}$
b) $\sqrt[]{6}$ – 1 va 3
a)$\frac{1}{4}$$\sqrt{82}$= $\frac{√82}{4}$ $>$6$\sqrt{}\frac{1}{7}$ =$\frac{6√7}{7}$
b)$\sqrt{6-1}$ =$\sqrt{5}$
$\sqrt{9}$ $= 3$
$⇒$$\sqrt{9}$$ >$$\sqrt{5}$
Học tốt ạ
a) `(1/4sqrt82)^2=1/16. 82=41/8=5 1/8`
`(6sqrt(1/7))^2=36. 1/7=36/7=5 1/7`
Vì `5 1/7>5 1/8⇒1/4sqrt82<6sqrt(1/7)`
b) `3=4-1=sqrt16 -1>sqrt6 -1`