so sanh a va b a=10^10+2/10^10-1 , b=10^10/10^10-3

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1. `A=(10^10+2)/(10^10-1)`

   `A=1+3/(10^10-1)`

   `B=(10^10)/(10^10-3)`

   `B=1+3/(10^10-3)`

   Ta có: 

   `10^10-1>10^10-3`

   `⇒3/(10^10-1)<3/(10^10-3)`

   `⇒A<B`

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2. Ta có : 

   `A-1=1-{10^10+2}/{10^10-1}={10^10+2}/{10^10-1}-{10^10-1}/{10^10-1}=3/{10^10-1}`

   `B-1=1-10^10/{10^10-3}=10^10/10^10-10^10/{10^10-3}=3/{10^10-3}`

   Vì `3/10^10-1>3/10^10-3`

   `⇒A>B`

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