so sánh theo tính chất bắc cầu 13/38 và -12/-37 27/09/2021 Bởi Nevaeh so sánh theo tính chất bắc cầu 13/38 và -12/-37
Đáp án: Giải thích các bước giải: \(\begin{array}{*{20}{l}}{\frac{{13}}{{38}}{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} va{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} \frac{{ – 12}}{{ – 37}}}\\{Ta{\mkern 1mu} co:{\mkern 1mu} }\\{\frac{{ – 12}}{{ – 37}} = \frac{{12}}{{37}} < \frac{{12}}{{36}} = \frac{1}{3}{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} \left( 1 \right)}\\{{\mkern 1mu} \frac{{13}}{{38}} > \frac{{13}}{{39}} = \frac{1}{3}{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} \left( 2 \right)}\\{Tu{\mkern 1mu} {\mkern 1mu} \left( 1 \right){\mkern 1mu} {\mkern 1mu} {\mkern 1mu} va{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} \left( 2 \right) \Rightarrow \frac{{ – 12}}{{ – 37}} < \frac{1}{3} < \frac{{13}}{{38}}}\\{ \Rightarrow \frac{{ - 12}}{{ - 37}} < \frac{{13}}{{38}}}\end{array}\) Bình luận
Đáp án:
Giải thích các bước giải:
\(\begin{array}{*{20}{l}}{\frac{{13}}{{38}}{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} va{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} \frac{{ – 12}}{{ – 37}}}\\{Ta{\mkern 1mu} co:{\mkern 1mu} }\\{\frac{{ – 12}}{{ – 37}} = \frac{{12}}{{37}} < \frac{{12}}{{36}} = \frac{1}{3}{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} \left( 1 \right)}\\{{\mkern 1mu} \frac{{13}}{{38}} > \frac{{13}}{{39}} = \frac{1}{3}{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} \left( 2 \right)}\\{Tu{\mkern 1mu} {\mkern 1mu} \left( 1 \right){\mkern 1mu} {\mkern 1mu} {\mkern 1mu} va{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} \left( 2 \right) \Rightarrow \frac{{ – 12}}{{ – 37}} < \frac{1}{3} < \frac{{13}}{{38}}}\\{ \Rightarrow \frac{{ - 12}}{{ - 37}} < \frac{{13}}{{38}}}\end{array}\)
13/38>-12/38
-12/37