SO3+H20=> H2SO4+NAOH=> K2O+H2O=> Al2O3+H2SO4=> Ca(OH)2+NA2CO3=> Fe+HCl=> Cu(OH)2=> Ca(OH)2+HNO3=> Mg(OH)2+HCl=> KOH+H2SO4=> Zn+FeSO4=> H2SO4+Ba(NO3)2=

0 bình luận về “SO3+H20=> H2SO4+NAOH=> K2O+H2O=> Al2O3+H2SO4=> Ca(OH)2+NA2CO3=> Fe+HCl=> Cu(OH)2=> Ca(OH)2+HNO3=> Mg(OH)2+HCl=> KOH+H2SO4=> Zn+FeSO4=> H2SO4+Ba(NO3)2=”

1. $SO_3+H_2O\to H_2SO_4$

   $H_2SO_4+2NaOH\to Na_2SO_4+2H_2O$

   $K_2O+H_2O\to 2KOH$

   $Al_2O_3+3H_2SO_4\to Al_2(SO_4)_3+3H_2O$

   $Ca(OH)_2+Na_2CO_3\to CaCO_3+2NaOH$

   $Fe+2HCl\to FeCl_2+H_2$

   $Cu(OH)_2\xrightarrow{t^o} CuO+H_2O$

   $Ca(OH)_2+2HNO_3\to Ca(NO_3)_2+2H_2O$

   $Mg(OH)_2+2HCl\to MgCl_2+2H_2O$

   $2KOH+H_2SO_4\to K_2SO_4+2H_2O$

   $Zn+FeSO_4\to ZnSO_4+Fe$

   $H_2SO_4+Ba(NO_3)_2\to BaSO_4+2HNO_3$

   $NaHCO_3+HCl\to NaCl+CO_2+H_2O$

   $K_2CO_3+BaCl_2\to BaCO_3+2KCl$ 

    

   Trả lời

2. $SO_{3}$ + $H_{2}$$O_{}$ → $H_{2}$$SO_{4}$

   $H_{2}$$SO_{4}$ + $2NaOH_{}$ → $Na_{2}$$SO_{4}$ + $2H_{2}$$O_{}$

   $K_{2}$$O_{}$ + $H_{2}$$O_{}$ → $2KOH_{}$

   $Al_{2}$$O_{3}$ + $3H_{2}$$SO_{4}$ → $Al_{2}$$(SO_{4})$$_{3}$ + $3H_{2}$$O_{}$

   $Ca(OH)_{2}$ + $Na_{2}$$CO_{3}$ → $CaCO_{3}$ ↓ + $2NaOH_{}$

   $Fe_{}$ + $2HCl_{}$ → $FeCl_{2}$ + $H_{2}$ ↑

   $Cu(OH)_{2}$ → $CuO_{}$ + $H_{2}$$O_{}$

   $Ca(OH)_{2}$ + $2HNO_{3}$ → $Ca(NO_{3})$$_{2}$ + $2H_{2}$$O_{}$

   $Mg(OH)_{2}$ + $2HCl_{}$ → $MgCl_{}$ + $2H_{2}$$O_{}$

   $2KOH_{123}$ + $H_{2}$$SO_{4}$ → $K_{2}$$SO_{4}$ + $2H_{2}$$O_{}$

   $Zn_{}$ + $FeSO_{4}$ → $ZnSO_{4}$ + $Fe_{}$↓

   $H_{2}$$SO_{4}$ + $Ba(NO_{3})$$_{2}$ → $BaSO_{4}$ ↓ + $2HNO_{3}$

   $NaHCO_{3}$ + $HCL_{}$ → $NaCl_{}$ + $H_{2}$$O_{}$ + $CO_{2}$ ↑

   $K_{2}$$CO_{3}$ + $BaCl_{2}$ → $BaCO_{3}$ ↓+ $2KCl_{}$

   Nhớ cho mik ctlhn nhé!!!

   Trả lời