$\sqrt[2]{\sqrt[2]{5}-\sqrt[2]{3-\sqrt[2]{29-12\sqrt[2]{5}}}}$ 20/09/2021 Bởi Eliza $\sqrt[2]{\sqrt[2]{5}-\sqrt[2]{3-\sqrt[2]{29-12\sqrt[2]{5}}}}$
$\sqrt{\sqrt{5}-\sqrt{3-\sqrt{29-12\sqrt{5}}}}$ =$\sqrt{\sqrt{5}-\sqrt{3-\sqrt{29-6\sqrt{20}}}}$ =$\sqrt{\sqrt{5}-\sqrt{3-\sqrt{20-2.\sqrt{20}.3+9}}}$ =$\sqrt{\sqrt{5}-\sqrt{3-\sqrt{(\sqrt{20}-3)^2}}}$ =$\sqrt{\sqrt{5}-\sqrt{3-(\sqrt{20}-3)}}$ =$\sqrt{\sqrt{5}-\sqrt{6-\sqrt{20}}}$ =$\sqrt{\sqrt{5}-\sqrt{5-2.1.\sqrt{5}+1}}$ =$\sqrt{\sqrt{5}-\sqrt{(\sqrt{5}-1)^2}}$ =$\sqrt{\sqrt{5}-(\sqrt{5}-1)}$ =$\sqrt{1}$ =1 Bình luận
$\sqrt{\sqrt{5}-\sqrt{3-\sqrt{29-12\sqrt{5}}}}$
=$\sqrt{\sqrt{5}-\sqrt{3-\sqrt{29-6\sqrt{20}}}}$
=$\sqrt{\sqrt{5}-\sqrt{3-\sqrt{20-2.\sqrt{20}.3+9}}}$
=$\sqrt{\sqrt{5}-\sqrt{3-\sqrt{(\sqrt{20}-3)^2}}}$
=$\sqrt{\sqrt{5}-\sqrt{3-(\sqrt{20}-3)}}$
=$\sqrt{\sqrt{5}-\sqrt{6-\sqrt{20}}}$
=$\sqrt{\sqrt{5}-\sqrt{5-2.1.\sqrt{5}+1}}$
=$\sqrt{\sqrt{5}-\sqrt{(\sqrt{5}-1)^2}}$
=$\sqrt{\sqrt{5}-(\sqrt{5}-1)}$
=$\sqrt{1}$
=1
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