Toán Thu gọn biểu thức sau. A=3y^2[(2y-1)+y+1]-y(1-y+y^2)-y^2+y 10/10/2021 By Genesis Thu gọn biểu thức sau. A=3y^2[(2y-1)+y+1]-y(1-y+y^2)-y^2+y
$3y^2[(2y-1)+y+1]-y(1-y+y^2)-y^2+y$ $=3y^2.3y-y+y^2-y^3-y^2+y$ $=9y^3-y+y^2-y^3-y^2+y$ $=(9y^3-y^3)+(-y+y)+(y^2-y^2)$ $=8y^3$ Trả lời
`A=3y^2[(2y-1)+y+1]-y(1-y+y^2)-y^2+y` `A=3y^2[2y-1+y+1]-y(1-y+y^2)-y^2+y` `A=3y^2*3y-y+y^2-y^3-y^2+y` `A=9y^3-y+y^2-y^3-y^2+y` `A=8y^3` Trả lời
$3y^2[(2y-1)+y+1]-y(1-y+y^2)-y^2+y$
$=3y^2.3y-y+y^2-y^3-y^2+y$
$=9y^3-y+y^2-y^3-y^2+y$
$=(9y^3-y^3)+(-y+y)+(y^2-y^2)$
$=8y^3$
`A=3y^2[(2y-1)+y+1]-y(1-y+y^2)-y^2+y`
`A=3y^2[2y-1+y+1]-y(1-y+y^2)-y^2+y`
`A=3y^2*3y-y+y^2-y^3-y^2+y`
`A=9y^3-y+y^2-y^3-y^2+y`
`A=8y^3`