Thực hiên phép tính “A = 1 2/5 X 3/8 + 7/5 X 5/8 -7 2/5″ ” B = 2 2/5 x (2/3 – 1/6 ) + 1/3 : 2 1/3″

Thực hiên phép tính
“A = 1 2/5 X 3/8 + 7/5 X 5/8 -7 2/5″
” B = 2 2/5 x (2/3 – 1/6 ) + 1/3 : 2 1/3″

0 bình luận về “Thực hiên phép tính “A = 1 2/5 X 3/8 + 7/5 X 5/8 -7 2/5″ ” B = 2 2/5 x (2/3 – 1/6 ) + 1/3 : 2 1/3″”

  1. Đáp án:

    `A= 1 2/5 xx 3/8 + 7/5 xx 5/8 -7 2/5`

     `A=7/5 xx 3/8 + 7/5 xx 5/8 – 37/5`

    `A= 7/5 xx (3/8 + 5/8) -37/5`

    `A=7/5 xx 1 -37/5=7/5- 37/5=-30/5=-6`

    `B=2 2/5 xx (2/3 -1/6) + 1/3 : 2 1/3`

    `B= 12/5 xx (4/6 -1/6) + 1/3 : 7/3`

    `B=12/5 xx 1/2 + 1/3 xx 3/7`

    `B=6/5 + 1/7=42/35 + 5/35=47/35`

    XIN HAY NHẤT NHA

    anhchangtienganh

    Bình luận
  2. `text{@dg}`

    $A=1\frac{2}{5} . \frac{3}{8} + \frac{7}{5} . \frac{5}{8} – 7 \frac{2}{5}$

    $=\frac{7}{5} . \frac{3}{8} + \frac{7}{5} . \frac{5}{8} – \frac{37}{5}$

    $=\frac{7}{5} . (\frac{3}{8} + \frac{5}{8}) – \frac{37}{5}$

    $= \frac{7}{5} . 1 – \frac{37}{5}$

    $= \frac{-30}{5} = -6$

    $B= 2\frac{2}{5} . (\frac{2}{3} – \frac{1}{6}) + \frac{1}{3} : 2\frac{1}{3}$

    $= \frac{12}{5} . (\frac{2}{3} – \frac{1}{6}) + \frac{1}{3} : \frac{7}{3}$

    $=\frac{12}{5} . \frac{1}{2} + \frac{1}{3} : \frac{7}{3}$

    $= \frac{6}{5} + \frac{1}{7}$

    $=\frac{47}{35}$.

    Bình luận

Viết một bình luận