thực hiện phép tính a) x+1/2x+6 + 2x+3/x² +3x b) 3/2x+6 – x-6/2x² +6x 25/10/2021 Bởi Valerie thực hiện phép tính a) x+1/2x+6 + 2x+3/x² +3x b) 3/2x+6 – x-6/2x² +6x
Giải thích các bước giải: a, `(x+1)/(2x+6) + (2x+3)/(x^2+3x)` `(x+1)/(2x+6) + (2x+3)/(x(x+3))` `(x(x+1)+2(2x+3))/(2x(x+3))` `(x^2+x+4x+6)/(2x(x+3))` `(x^2+3x+2x+6)/(2x(x+3))` `(x(x+3)+2(x+3))/(2x(x+3))` `((x+3)(x+2))/(2x(x+3))` `(x+2)/(2x)` b, `(3)/(2x+6) – (x-6)/(2x^2+6x)` `(3)/(2(x+3)) – (x-6)/(2x(x+3))` `(3x-(x-6))/(2x(x+3))` `(2(x+3))/(2x(x+3))` `1/x` Cho em xin hay nhất Bình luận
Giải thích các bước giải: $a)\dfrac{x+1}{2x+6}+\dfrac{2x+3}{x^2+3x}$ $=\dfrac{x(x+1)}{2x(x+3)}+\dfrac{2(2x+3)}{2x(x+3)}$ $=\dfrac{x^2+x+4x+6}{2x(x+3)}$ $=\dfrac{x^2+5x+6}{2x(x+3)}$ $=\dfrac{(x+2)(x+3)}{2x(x+3)}$ $=\dfrac{x+2}{2x}$ $b)\dfrac{3}{2x+6}-\dfrac{x-6}{2x^2+6x}$ $=\dfrac{3x}{2x(x+3)}-\dfrac{x-6}{2x(x+3)}$ $=\dfrac{2x+6}{x(2x+6)}$ $=\dfrac{1}{x}$ Bình luận
Giải thích các bước giải:
a, `(x+1)/(2x+6) + (2x+3)/(x^2+3x)`
`(x+1)/(2x+6) + (2x+3)/(x(x+3))`
`(x(x+1)+2(2x+3))/(2x(x+3))`
`(x^2+x+4x+6)/(2x(x+3))`
`(x^2+3x+2x+6)/(2x(x+3))`
`(x(x+3)+2(x+3))/(2x(x+3))`
`((x+3)(x+2))/(2x(x+3))`
`(x+2)/(2x)`
b, `(3)/(2x+6) – (x-6)/(2x^2+6x)`
`(3)/(2(x+3)) – (x-6)/(2x(x+3))`
`(3x-(x-6))/(2x(x+3))`
`(2(x+3))/(2x(x+3))`
`1/x`
Cho em xin hay nhất
Giải thích các bước giải:
$a)\dfrac{x+1}{2x+6}+\dfrac{2x+3}{x^2+3x}$
$=\dfrac{x(x+1)}{2x(x+3)}+\dfrac{2(2x+3)}{2x(x+3)}$
$=\dfrac{x^2+x+4x+6}{2x(x+3)}$
$=\dfrac{x^2+5x+6}{2x(x+3)}$
$=\dfrac{(x+2)(x+3)}{2x(x+3)}$
$=\dfrac{x+2}{2x}$
$b)\dfrac{3}{2x+6}-\dfrac{x-6}{2x^2+6x}$
$=\dfrac{3x}{2x(x+3)}-\dfrac{x-6}{2x(x+3)}$
$=\dfrac{2x+6}{x(2x+6)}$
$=\dfrac{1}{x}$