Thực hiện phép tính `A = [ (2/193 – 3/386) . 193/17 + 33/34] : [(7/1931 + 11/3862) . 1931/25 + 9/2]`

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1. Đáp án+Giải thích các bước giải:

   $A=\left[\left(\dfrac{2}{193}-\dfrac{3}{386}\right).\dfrac{193}{17}+\dfrac{33}{34}\right]:\left[\left(\dfrac{7}{1931}+\dfrac{11}{3862}\right).\dfrac{1931}{25}+\dfrac{9}{2}\right]\\=\left[\left(\dfrac{4}{368}-\dfrac{3}{386}\right).\dfrac{193}{17}+\dfrac{33}{34}\right]:\left[\left(\dfrac{14}{3862}+\dfrac{11}{3862}\right).\dfrac{1931}{25}+\dfrac{9}{2}\right]\\=\left[\dfrac1{368}.\dfrac{193}{17}+\dfrac{33}{34}\right]:\left[\dfrac{25}{3862}.\dfrac{1931}{25}+\dfrac{9}{2}\right]\\=\left[\dfrac{1}{34}+\dfrac{33}{34}\right]:\left[\dfrac{1}{2}+\dfrac{9}{2}\right]\\=1:5\\=\dfrac1{5}$ 

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2. Đáp án:

    `A=0,2`

   Giải thích các bước giải:

   `A = [ (2/193 – 3/386) * 193/17 + 33/34] ÷ [(7/1931 + 11/3862) * 1931/25 + 9/2]`

   `=[2/193*193/17-3/385*193/17+33/34]÷[7/1931*1931/25+11/3862*1931/25+9/2]`

   `=[2/17-3/34+33/34]÷[7/25+11/50+9/2]`

   `=[2/17-(3/34-33/34)]÷[1/2+9/2]`

   `=[2/17+15/17]÷5`

   `=1÷5`

   `=0,2`

   vậy `A=0,2`

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