thực hiện phép tính: a, $\sqrt[]{3}$ -$\sqrt[]{5}$ .($\sqrt[]{10}$ -$\sqrt[]{2}$ ).(3+$\sqrt[]{5}$ ) 03/09/2021 Bởi Julia thực hiện phép tính: a, $\sqrt[]{3}$ -$\sqrt[]{5}$ .($\sqrt[]{10}$ -$\sqrt[]{2}$ ).(3+$\sqrt[]{5}$ )
$\sqrt{3}-\sqrt{5}(\sqrt{10}-\sqrt{2}).(3+\sqrt{5})\\=\sqrt{3}+(-\sqrt{50}+\sqrt{10}).(3+\sqrt{5})\\=\sqrt{3}+(-5\sqrt{2}+\sqrt{10}).(3+\sqrt{5})\\=\sqrt{3}-15\sqrt{2}-5\sqrt{10}+3\sqrt{10}+\sqrt{50}\\=\sqrt{3}-15\sqrt{2}-5\sqrt{10}+3\sqrt{10}+5\sqrt{2}\\=\sqrt{3}-10\sqrt{2}-2\sqrt{10}$ Bình luận
$\sqrt{3}-\sqrt{5}(\sqrt{10}-\sqrt{2}).(3+\sqrt{5})\\=\sqrt{3}+(-\sqrt{50}+\sqrt{10}).(3+\sqrt{5})\\=\sqrt{3}+(-5\sqrt{2}+\sqrt{10}).(3+\sqrt{5})\\=\sqrt{3}-15\sqrt{2}-5\sqrt{10}+3\sqrt{10}+\sqrt{50}\\=\sqrt{3}-15\sqrt{2}-5\sqrt{10}+3\sqrt{10}+5\sqrt{2}\\=\sqrt{3}-10\sqrt{2}-2\sqrt{10}$