Thực hiện phép tính $\frac{1}{x(x+y)}$+ $\frac{1}{y(x+y)}$+ $\frac{1}{x(x-y)}$+ $\frac{1}{y(y-x)}$ 02/12/2021 Bởi Rose Thực hiện phép tính $\frac{1}{x(x+y)}$+ $\frac{1}{y(x+y)}$+ $\frac{1}{x(x-y)}$+ $\frac{1}{y(y-x)}$
`\text{~~Holi~~}` `1/(x(x+y))+1/(y(x+y))+1/(x(x-y))+1/(y(y-x))` `= 1/(x(x+y))+1/(y(x+y))+1/(x(x-y))-1/(y(x-y))` `= (y(x-y)+x(x-y)+y(x+y)-x(x+y))/(xy(x+y)(x-y))` `= (xy-y^2+x^2-xy+xy+y^2-x^2-xy)/(xy(x^2-y^2)` `= 0/(xy(x^2-y^2)` `= 0` Bình luận
`\text{~~Holi~~}`
`1/(x(x+y))+1/(y(x+y))+1/(x(x-y))+1/(y(y-x))`
`= 1/(x(x+y))+1/(y(x+y))+1/(x(x-y))-1/(y(x-y))`
`= (y(x-y)+x(x-y)+y(x+y)-x(x+y))/(xy(x+y)(x-y))`
`= (xy-y^2+x^2-xy+xy+y^2-x^2-xy)/(xy(x^2-y^2)`
`= 0/(xy(x^2-y^2)`
`= 0`