Tìm x: ( x+1/5)^2 + 18/25= 27/25 Giúp mình nha:)) 14/10/2021 Bởi Alaia Tìm x: ( x+1/5)^2 + 18/25= 27/25 Giúp mình nha:))
$(x+\dfrac{1}{5})^2 + \dfrac{18}{25} = \dfrac{27}{25}$ $⇔ (x+\dfrac{1}{5})^2 = \dfrac{9}{25}$ $⇒$ \(\left[ \begin{array}{l}x+\dfrac{1}{5}=\dfrac{3}{5}\\x+\dfrac{1}{5} = \dfrac{-3}{5}\end{array} \right.\) $⇒$ \(\left[ \begin{array}{l}x=\dfrac{2}{5}\\x=\dfrac{-4}{5}\end{array} \right.\) Vậy $x$ ∈ {$\dfrac{-4}{5};\dfrac{2}{5}$} Bình luận
Đáp án:
Giải thích các bước giải:
đây
$(x+\dfrac{1}{5})^2 + \dfrac{18}{25} = \dfrac{27}{25}$
$⇔ (x+\dfrac{1}{5})^2 = \dfrac{9}{25}$
$⇒$ \(\left[ \begin{array}{l}x+\dfrac{1}{5}=\dfrac{3}{5}\\x+\dfrac{1}{5} = \dfrac{-3}{5}\end{array} \right.\)
$⇒$ \(\left[ \begin{array}{l}x=\dfrac{2}{5}\\x=\dfrac{-4}{5}\end{array} \right.\)
Vậy $x$ ∈ {$\dfrac{-4}{5};\dfrac{2}{5}$}