Tìm x : | x+2 | = 0 | X-5|= |-7| |X-3|=7-( -2) (7-x ) – (25+7) = – 25 17/08/2021 Bởi Madeline Tìm x : | x+2 | = 0 | X-5|= |-7| |X-3|=7-( -2) (7-x ) – (25+7) = – 25
| x+2 | = 0 *TH1: x+2 = 0 x = -2 *TH2 : -x -2=0 x = -2 | X-5|= |-7| *TH1 : x -5= -7 x = -2 *TH2 : -x +5= -7 x = 12 |X-3|=7-( -2) *TH1 : x -3= -14 x = -11 *TH2 : -x +3= -14 x = 17 (7-x ) – (25+7) = – 25 7-x – 25-7 = -25 x = 0 Bình luận
a, | x+2 | = 0 ⇔ x+2=0 ⇔ x=-2 b, | x-5|= |-7| ⇔ | x-5|=7 ⇔ \(\left[ \begin{array}{l}x-5=7\\x-5=-7\end{array} \right.\) ⇔ \(\left[ \begin{array}{l}x=12\\x=-2\end{array} \right.\) c, |x-3|=7-( -2) ⇔ |x-3|=9 ⇔ \(\left[ \begin{array}{l}x-3=9\\x-5=-9\end{array} \right.\) ⇔ \(\left[ \begin{array}{l}x=12\\x=-4\end{array} \right.\) d, (7-x ) – (25+7) = – 25 ⇔ 7-x-25-7=-25 ⇔ -x-25=-25 ⇔ x=0 Bình luận
| x+2 | = 0
*TH1:
x+2 = 0
x = -2
*TH2 :
-x -2=0
x = -2
| X-5|= |-7|
*TH1 :
x -5= -7
x = -2
*TH2 :
-x +5= -7
x = 12
|X-3|=7-( -2)
*TH1 :
x -3= -14
x = -11
*TH2 :
-x +3= -14
x = 17
(7-x ) – (25+7) = – 25
7-x – 25-7 = -25
x = 0
a, | x+2 | = 0
⇔ x+2=0
⇔ x=-2
b, | x-5|= |-7|
⇔ | x-5|=7
⇔ \(\left[ \begin{array}{l}x-5=7\\x-5=-7\end{array} \right.\)
⇔ \(\left[ \begin{array}{l}x=12\\x=-2\end{array} \right.\)
c, |x-3|=7-( -2)
⇔ |x-3|=9
⇔ \(\left[ \begin{array}{l}x-3=9\\x-5=-9\end{array} \right.\)
⇔ \(\left[ \begin{array}{l}x=12\\x=-4\end{array} \right.\)
d, (7-x ) – (25+7) = – 25
⇔ 7-x-25-7=-25
⇔ -x-25=-25
⇔ x=0