Tìm x x^2-x+1/4=0 x^3-0.25x=0 x^2-10x=-25 4x^2-4x=-1 8x^3+12x^2+6x+1=0 21/09/2021 Bởi Rose Tìm x x^2-x+1/4=0 x^3-0.25x=0 x^2-10x=-25 4x^2-4x=-1 8x^3+12x^2+6x+1=0
Tìm x x^2 – x + 1/4 = 0 x(x -1/2) = 0 x = 0 x – 1/2 = 0 x = 1/2 x^3 – 0.25x = 0 x(x^2 – 0.25) = 0 x = 0 x^2 – 0,25 = 0 x = 0,5 x^2 – 10x =-25 x(x – 10) = -25 x = -25 x – 10 = -25 x = -15 4x^2 – 4x = -1 4x(x – 1) = -1 4x = -1 → x = -1/4 x – 1 = -1 → x = 0 8x^3 + 12x^2 + 6x + 1 = 0 2x(4x^2 + 6x + 3x + 1) = 0 2x(4x^2 + 9x + 1) = 0 2x = 0 → x = 0 4x^2 + 9x + 1 = 0 -2 khác 0 Bình luận
Tìm x
x^2 – x + 1/4 = 0
x(x -1/2) = 0
x = 0
x – 1/2 = 0
x = 1/2
x^3 – 0.25x = 0
x(x^2 – 0.25) = 0
x = 0
x^2 – 0,25 = 0
x = 0,5
x^2 – 10x =-25
x(x – 10) = -25
x = -25
x – 10 = -25
x = -15
4x^2 – 4x = -1
4x(x – 1) = -1
4x = -1 → x = -1/4
x – 1 = -1 → x = 0
8x^3 + 12x^2 + 6x + 1 = 0
2x(4x^2 + 6x + 3x + 1) = 0
2x(4x^2 + 9x + 1) = 0
2x = 0 → x = 0
4x^2 + 9x + 1 = 0
-2 khác 0