Toán tìm x (2x-3)(x+1)(4x^3-6x^2-6x):(-2x)=18 03/09/2021 By Savannah tìm x (2x-3)(x+1)(4x^3-6x^2-6x):(-2x)=18
Đáp án:(2x-3)(x+1)(4x^3-6x^2-6x):(-2x)=18 =(2x^2+2x-3x-3)(-2x^2+3x+3)=18 =2x^2-x-3-2x^2+3x+3=18 =2x=18 x=9 Trả lời
Đáp án:(2x-3)(x+1)(4x^3-6x^2-6x):(-2x)=18
=(2x^2+2x-3x-3)(-2x^2+3x+3)=18
=2x^2-x-3-2x^2+3x+3=18
=2x=18
x=9