Tìm x: 2 và 1/4.(x-7 và1/3)=1,5 (2,8.x-32) : 2/3=-90 12/08/2021 Bởi Abigail Tìm x: 2 và 1/4.(x-7 và1/3)=1,5 (2,8.x-32) : 2/3=-90
`a) 2 1/4.(x-7 1/3)=1,5``=> 9/4. ( x – 22/3) =3/2``=> x-22/3 = 3/2 : 9/4``=> x-22/3 = 2/3``=> x = 2/3 + 22/3 `` => x = 8`Vậy `x=8` `b) (2,8.x-32) : 2/3=-90``=> 2,8x – 32 = -90 . 2/3``=> 2,8x – 32 = -60``=> 2,8x = -60 + 32``=> 2,8x = -28``=> x = -28 :2,8``=> x = -10`Vậy `x=-10` Bình luận
2`1/4`.(`x`-`7“1/3`)=`1,5` `9/4`. ( `x` -`22/3`) = `3/2` ( `x` – `22/3`) =`3/2`: `9/4` `x` – `22/3` = `2/3` `x` = `2/3` + `22/3` `x` = `8` Vậy `x` = `8` (2,8.`x`-`32`) : `2/3`=-90 (2,8 . `x` – 32 ) = `-90` . `2/3` 2,8 . `x` – 32 =-60 `2,8` . `x` = -60 + 32 `2,8` . `x` = -28 `x` = -28 : 2,8 `x` = `-10` Vậy `x` = `-10` Bình luận
`a) 2 1/4.(x-7 1/3)=1,5`
`=> 9/4. ( x – 22/3) =3/2`
`=> x-22/3 = 3/2 : 9/4`
`=> x-22/3 = 2/3`
`=> x = 2/3 + 22/3 `
` => x = 8`
Vậy `x=8`
`b) (2,8.x-32) : 2/3=-90`
`=> 2,8x – 32 = -90 . 2/3`
`=> 2,8x – 32 = -60`
`=> 2,8x = -60 + 32`
`=> 2,8x = -28`
`=> x = -28 :2,8`
`=> x = -10`
Vậy `x=-10`
2`1/4`.(`x`-`7“1/3`)=`1,5`
`9/4`. ( `x` -`22/3`) = `3/2`
( `x` – `22/3`) =`3/2`: `9/4`
`x` – `22/3` = `2/3`
`x` = `2/3` + `22/3`
`x` = `8`
Vậy `x` = `8`
(2,8.`x`-`32`) : `2/3`=-90
(2,8 . `x` – 32 ) = `-90` . `2/3`
2,8 . `x` – 32 =-60
`2,8` . `x` = -60 + 32
`2,8` . `x` = -28
`x` = -28 : 2,8
`x` = `-10`
Vậy `x` = `-10`