tìm x 2009 – ( 4 5/9 + x – 7 7/18 ) : 15 2/3 = 2008 08/09/2021 Bởi Josephine tìm x 2009 – ( 4 5/9 + x – 7 7/18 ) : 15 2/3 = 2008
$Giải $ $2009-(4$$\dfrac{5}{9}$ $+x-7$$\dfrac{7}{18}$ $):15$$\dfrac{2}{3}$ $= 2008$ $=>$ $2009-($ $\dfrac{41}{9}$$+x-$ $\dfrac{133}{18}$$)$ $:$ $\dfrac{47}{3}$ $=2008$ $=>$ $($ $\dfrac{41}{9}$$+x-$ $\dfrac{133}{18}$$)$ $:$ $\dfrac{47}{3}$ $=2009-2008$$=>$ $(x-$ $\dfrac{17}{6}$ $):$ $\dfrac{47}{3}$ $=1$ $=>$ $x-$ $\dfrac{17}{6}$ $=1.$ $\dfrac{47}{3}$ $=>$ $x-$ $\dfrac{17}{6}$ $=$ $\dfrac{47}{3}$$=>$ $x=$ $\dfrac{37}{2}$ $Vậy$ $x=$ $\dfrac{37}{2}$ Bình luận
$#Đáp án + Giải thích các bước giải:$ `2009 – ( 4 5/9 + x – 7 7/18 ) ÷ 15 2/3 = 2008` `-> 2009 – (41/9 + x – 133/18) ÷ 47/3 = 2008``-> (41/9 + x – 133/18)÷ 47/3 = 2009 – 2008``-> (x – 17/6) ÷ 47/3 = 1``-> x – 17/6 = 1×47/3` `-> x – 17/6 = 47/3``-> x = 47/3 + 17/6` Vậy `x=37/2` $#Na$ $#XIN HAY NHẤT AK$ Bình luận
$Giải $
$2009-(4$$\dfrac{5}{9}$ $+x-7$$\dfrac{7}{18}$ $):15$$\dfrac{2}{3}$ $= 2008$
$=>$ $2009-($ $\dfrac{41}{9}$$+x-$ $\dfrac{133}{18}$$)$ $:$ $\dfrac{47}{3}$ $=2008$
$=>$ $($ $\dfrac{41}{9}$$+x-$ $\dfrac{133}{18}$$)$ $:$ $\dfrac{47}{3}$ $=2009-2008$
$=>$ $(x-$ $\dfrac{17}{6}$ $):$ $\dfrac{47}{3}$ $=1$
$=>$ $x-$ $\dfrac{17}{6}$ $=1.$ $\dfrac{47}{3}$
$=>$ $x-$ $\dfrac{17}{6}$ $=$ $\dfrac{47}{3}$
$=>$ $x=$ $\dfrac{37}{2}$
$Vậy$ $x=$ $\dfrac{37}{2}$
$#Đáp án + Giải thích các bước giải:$
`2009 – ( 4 5/9 + x – 7 7/18 ) ÷ 15 2/3 = 2008`
`-> 2009 – (41/9 + x – 133/18) ÷ 47/3 = 2008`
`-> (41/9 + x – 133/18)÷ 47/3 = 2009 – 2008`
`-> (x – 17/6) ÷ 47/3 = 1`
`-> x – 17/6 = 1×47/3`
`-> x – 17/6 = 47/3`
`-> x = 47/3 + 17/6`
Vậy `x=37/2`
$#Na$
$#XIN HAY NHẤT AK$