Tìm x x+2017/2+x+2017/6+x+2017/12=0 (0.1.2.3.4…999+100%).x^2=64

Đáp án:

+`x=(-2017)`

+\(\left[ \begin{array}{l}x=8\\x=-8\end{array} \right.\) 

Giải thích các bước giải:

`**[x+2017]/2+[x+2017]/6+[x+2017]/12=0`
`(x+2017).(1/2+1/6+1/12)=0`
`(x+2017)(1/1.2+1/2.3+1/3.4)=0`
`(x+2017)(1-1/2+1/2-1/3+1/3-1/4)=0`
`(x+2017)(1-1/4)=0`
`(x+2017)(4/4-1/4)=0`
`(x+2017).3/4=0`
Vì `3/4 !=0`
`=>x+2017=0`
`x=0-2017`
`x=(-2017)`
Vậy `x=(-2017)`

`**(0.1.2.3.4…999+100%).x^2=64`
`(0+100/100).x^2=64`
`1.x^2=64`
`x^2=64`
Vì mũ chẵn sẽ có 2 đáp án.
`=>`\(\left[ \begin{array}{l}x^2=8^2\\x=(-8)^2\end{array} \right.\) `=>`\(\left[ \begin{array}{l}x=8\\x=-8\end{array} \right.\) 
Vậy \(\left[ \begin{array}{l}x=8\\x=-8\end{array} \right.\)