`(4x -3) – (x+5) = 3(10-x)` `4x -3 -x -5 = 30 – 3x` `4x – x + 3x = 30 + 5 +3` `6x = 38` `x= 38:6` `x= 19/3` Vậy `x= 19/3` Bình luận
c1:(4x-3)-x-5=3(10-x) (4????−3−????−5=3(10−????) x=19/3 c2:(4????−3)−(????+5)=3(10−????) 4????−3)−(????+5)=3(10−????) x=19/3 c3:4????−3−????−5=3(10−????) 4????−8−????=3(10−????) x=19/3 c4:4????−8−????=3(10−????) 3????−8=3(10−????) x=19/3 học tok Bình luận
`(4x -3) – (x+5) = 3(10-x)`
`4x -3 -x -5 = 30 – 3x`
`4x – x + 3x = 30 + 5 +3`
`6x = 38`
`x= 38:6`
`x= 19/3`
Vậy `x= 19/3`
c1:(4x-3)-x-5=3(10-x)
(4????−3−????−5=3(10−????)
x=19/3
c2:(4????−3)−(????+5)=3(10−????)
4????−3)−(????+5)=3(10−????)
x=19/3
c3:4????−3−????−5=3(10−????)
4????−8−????=3(10−????)
x=19/3
c4:4????−8−????=3(10−????)
3????−8=3(10−????)
x=19/3
học tok