Tìm x : a) X : 1/2 + 3/4 = 1 19/20 b) x + x x 1/3 + 5/18 = 1 1/6 22/07/2021 Bởi Samantha Tìm x : a) X : 1/2 + 3/4 = 1 19/20 b) x + x x 1/3 + 5/18 = 1 1/6
${a,x:}$ $\dfrac{1}{2}+$ $\dfrac{3}{4}=$ $1\dfrac{19}{20}$ ${x:}$ $\dfrac{1}{2}+$ $\dfrac{3}{4}=$ $\dfrac{39}{20}$ ${x:}$ $\dfrac{1}{2}=$ $\dfrac{39}{20}-$ $\dfrac{3}{4}$ ${x:}$ $\dfrac{1}{2}=$ $\dfrac{6}{5}$ ${x=}$ $\dfrac{6}{5}$ x $\dfrac{1}{2}$ ${x=}$ $\dfrac{3}{5}$ ${b,x+x}$ x $\dfrac{1}{3}+$ $\dfrac{5}{18}=$ $1\dfrac{1}{6}$ ${x+x}$ x $\dfrac{1}{3}+$ $\dfrac{5}{18}=$ $\dfrac{7}{6}$ ${x+x}$ x $\dfrac{1}{3}=$ $\dfrac{7}{6}-$ $\dfrac{5}{18}$ ${x+x}$ x $\dfrac{1}{3}=$ $\dfrac{8}{9}$ ${x}$ x $(1+\dfrac{1}{3})=$ $\dfrac{8}{9}$ ${x}$ x $\dfrac{4}{3}=$ $\dfrac{8}{9}$ ${x=}$ $\dfrac{8}{9}:$ $\dfrac{4}{3}$ ${x=}$ $\dfrac{2}{3}$ ~Xin hay nhất~ Bình luận
a)x:$\frac{1}{2}$ +$\frac{3}{4}$ =1$\frac{19}{20}$ x:$\frac{1}{2}$ =1$\frac{19}{20}$ -$\frac{3}{4}$ x:$\frac{1}{2}$ =1$\frac{1}{5}$ x=1$\frac{1}{5}$ .$\frac{1}{2}$ x=$\frac{3}{5}$ b)x+x.$\frac{1}{3}$ +$\frac{5}{18}$=1 $\frac{1}{6}$ x.(1+$\frac{1}{3}$ )=1$\frac{1}{6}$ -$\frac{5}{18}$ x.1$\frac{1}{3}$ =$\frac{8}{9}$ x=$\frac{8}{9}$ :1$\frac{1}{3}$ x=$\frac{2}{3}$ Bình luận
${a,x:}$ $\dfrac{1}{2}+$ $\dfrac{3}{4}=$ $1\dfrac{19}{20}$
${x:}$ $\dfrac{1}{2}+$ $\dfrac{3}{4}=$ $\dfrac{39}{20}$
${x:}$ $\dfrac{1}{2}=$ $\dfrac{39}{20}-$ $\dfrac{3}{4}$
${x:}$ $\dfrac{1}{2}=$ $\dfrac{6}{5}$
${x=}$ $\dfrac{6}{5}$ x $\dfrac{1}{2}$
${x=}$ $\dfrac{3}{5}$
${b,x+x}$ x $\dfrac{1}{3}+$ $\dfrac{5}{18}=$ $1\dfrac{1}{6}$
${x+x}$ x $\dfrac{1}{3}+$ $\dfrac{5}{18}=$ $\dfrac{7}{6}$
${x+x}$ x $\dfrac{1}{3}=$ $\dfrac{7}{6}-$ $\dfrac{5}{18}$
${x+x}$ x $\dfrac{1}{3}=$ $\dfrac{8}{9}$
${x}$ x $(1+\dfrac{1}{3})=$ $\dfrac{8}{9}$
${x}$ x $\dfrac{4}{3}=$ $\dfrac{8}{9}$
${x=}$ $\dfrac{8}{9}:$ $\dfrac{4}{3}$
${x=}$ $\dfrac{2}{3}$
~Xin hay nhất~
a)x:$\frac{1}{2}$ +$\frac{3}{4}$ =1$\frac{19}{20}$
x:$\frac{1}{2}$ =1$\frac{19}{20}$ -$\frac{3}{4}$
x:$\frac{1}{2}$ =1$\frac{1}{5}$
x=1$\frac{1}{5}$ .$\frac{1}{2}$
x=$\frac{3}{5}$
b)x+x.$\frac{1}{3}$ +$\frac{5}{18}$=1 $\frac{1}{6}$
x.(1+$\frac{1}{3}$ )=1$\frac{1}{6}$ -$\frac{5}{18}$
x.1$\frac{1}{3}$ =$\frac{8}{9}$
x=$\frac{8}{9}$ :1$\frac{1}{3}$
x=$\frac{2}{3}$